How does a bar chart make it easier to see the pattern in a data?

Chemistry

1 answer:

Vladimir [108]3 years ago

3 0

Bar graph is a visual tool that uses bars to compare data among categories

Explanation:

Bar charts compares the values between the categories. It is one of the easy method to check whether the data is discrete or continuous where discrete data is counted as number of political parties and continuous is measured in height or sales.

If the data has more than one value per category, a stacked or grouped bar charts allows you to see individual values and compare categories.

The stacked bar chart is ideal for comparing the sum of the components of each group. The stacked bar chart is not useful for comparing totals because the present of all respondents adds up to 100% roughly for every category.

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How many moles of nitrous oxide (N2O) are produced when 1.40 moles of ammonium nitrate (NH4NO3) decompes?

blagie [28]

Answer:

The answer to your question is 1.40 moles of N₂O

Explanation:

Balanced equation

NH₄NO₃ ⇒ N₂O + 2 H₂O

2 -------- N ---------- 2

4 ------- H ---------- 4

3 ------- O ---------- 3

Process

1.- From the balanced equation, we know that 1 mol of NH₄NO₃ produces 1 mol of N₂O so, we use proportions to find the number of moles produced when 1.40 moles of NH₄NO₃ react.

1 mol of NH₄NO₃ ------------- 1 mol of N₂O

1.40 moles -------------- x

x = (1.40 x 1) / 1

x = 1.40 moles of N₂O are produced

7 0

4 years ago

Then if I have 210.1 g barium chloride with 45g potassium...how many grams of potassium chloride will I produce?

Katarina [22]

Answer:

85.8 g

Explanation:

The molar mass of BaCl₂ is 208.233 g/mol, so 210.1 g is about ...

210.1/208.233 ≈ 1.009 mol

The molar mass of K is about 39.089 g/mol, so 45 g is about ...

45/39.089 ≈ 1.1509 mol

The balanced equation seems to be ...

BaCl₂ + 2K ↔ 2KCl + Ba

This reaction requires 2 moles of potassium for each mole of barium chloride, so the available potassium limits the reaction. The result is as many moles of potassium chloride as there are moles of potassium.

The 1.1509 moles of KCl, at 74.551 g/mol will have a mass of about 85.8 g.

The reaction produces 85.8 g of KCl.