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mash [69]
3 years ago
14

KE 1/2mv^2 is a for kinetic energy (KE) in terms of mass, m, and the velocity, v, of a moving object. Which choice shows a corre

ct way to express the mass in terms of the kinetic energy and velocity?
A. m=2KE/v^2, where v≠0
B. m=KE/2v^2, where v≠0
C. m √2KE/v, where v≠0
D. m= √KE/2v, where v≠0
Physics
2 answers:
aivan3 [116]3 years ago
7 0

Answer:Kinetic energy is directly proportional to the mass of the object and to the square of its velocity: K.E. = 1/2 m v2. If the mass has units of kilograms and the velocity of meters per second, the kinetic energy has units of kilograms-meters squared per second squared.

motikmotik3 years ago
6 0

energy = (1/2)*m*(v^2)

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<u>Answer:</u> The velocity of released alpha particle is 1.127\times 10^7m/s

<u>Explanation:</u>

According to law of conservation of momentum, momentum can neither be created nor be destroyed until and unless, an external force is applied.

For a system:

m_1v_1=m_2v_2

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m_1\text{ and }v_1 = Initial mass and velocity

m_2\text{ and }v_2 = Final mass and velocity

We are given:

m_1=238u\\v_1=1.895\times 10^{5}m/s\\m_2=4u\text{ (Mass of }\alpha \text{ -particle)}\\v_2=?m/s

Putting values in above equation, we get:

238\times 1.895\times 10^5=4\times v_2\\\\v_2=\frac{238\times 1.895\times 10^5}{4}=1.127\times 10^7m/s

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