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3 years ago

The sun produces large amounts of energy. By what process does the sun produce energy?

1 answer:

8 0

The sun produces energy by converting gravitational potential energy into radiation via quantum processes in the nucleus of the atoms.

Since the mass of the sun and it's temperature are not quite enough to generate nuclear FUSION on their own, quantum tunneling is the primary process by which nuclear fusion occurs in our sun, SOL. FISSION also occurs as a result of this fusion.

Additionally, gravitational potential energy is also the reason that supernovae are so bright. Cool!

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The 1811-1812 new madrid earthquakes were different from most california earthquakes because

g100num [7]

Answer:

New Madrid earthquakes are centered in a plate interior, meaning they were intraplate earthquakes.

Explanation:

The 1811-1812 new madrid earthquakes were different from most california earthquakes because the New Madrid earthquakes were centered in a North American plate interior caused by stress within the plates.

The New Madrid earthquakes often referred to as the "Tecumseh's Comet" was the biggest earthquake in America history.

4 0

3 years ago

Help please what law is happening in these pictures

Karolina [17]

Answer: boyles law I’m pretty sure

7 0

2 years ago

Modeled after the two satellites problem (slide 12 in Lecture13, Universal gravity), imagine now if the period of the satellite

ikadub [295]

Answer:

R = 6.3456 10⁴ mile

Explanation:

For this exercise we will use Newton's second law where force is gravitational force

F = m a

The satellite is in a circular orbit therefore the acceleration is centripetal

a = v² / r

Where the distance is taken from the center of the Earth

G m M / r² = m v² / r

G M / r = v²

The speed module is constant, let's use the uniform motion relationships, with the length of the circle is

d = 2π r

v = d / t

The time for a full turn is called period (T)

Let's replace

G M / r = (2π r / T)²

r³ = G M T²²2 / 4π²

r = ∛ (G M T² / 4π²)

We have the magnitudes in several types of units

T = 88.59 h (3600 s / 1h) = 3.189 10⁵ s

Re = 6.37 10⁶ m

Let's calculate

r = ∛ (6.67 10⁻¹¹ 5.98 10²⁴ (3,189 10⁵)²/4π²)

r = ∛ (1.027487 10²⁴)

r = 1.0847 10⁸ m

This is the distance from the center of the Earth, the distance you want the surface is

R = r - Re

R = 108.47 10⁶ - 6.37 10⁶

R = 102.1 10⁶ m

Let's reduce to miles

R = 102.1 10⁶ m (1 mile / 1609 m)

R = 6.3456 10⁴ mile

6 0

2 years ago

State the role of an electromotive force (EFF) in a current flow

bonufazy [111]

Answer:

The emf source acts as a charge pump, moving negative charges from the positive terminal to the negative terminal to maintain the potential difference. This increases the potential energy of the charges and, therefore, the electric potential of the charges.

Explanation:

MARK AS BRAINLEST!!

8 0

2 years ago

The Eco-Marathon is an annual competition sponsored by Shell Oil, in which participants build special vehicles to achieve the

OverLord2011 [107]

Answer:

(1) V=0.03348 gallons

(2) L= 576.813 km .

Explanation:

Write the relation between the density and volume for ethanol.

density ( ρ )= m/V

Volume ( V )= m/ρ .......... (1)

Here, V is the volume of ethanol, m is the mass of ethanol, and is the density of ethanol.

Write the relation between the specific gravity of ethanol and density of water

ρ=γ*ρ(water) ............. (2)

Here, is specific gravity of ethanol and is the density of water.

Determine the volume of ethanol by substituting equation (2) in equation (1)

V=m/γ*ρ(water)

Substitute 100 gm , for m, for , and 1000 kg/m for.

V= $\frac{100*10^{-3} }{0.789*1000}$

V=0.000112674 $m^{3$

Convert m³ to gallons

V= (0.000112674*264.172 )

V=0.03348 gallons

Step 2:

Determine the distance travelled by the special vehicle named “Micro joule” runs with ethanol.

L=C*V .......... (3)

Here, is the rate of consumption of ethanol by Micro joule.

Substitute 10,705 mi/gallons for C and 0.03348 gallons for .

By using eq. 3.

L= 10750*0.03348

L=358.416 mi.

Convert the distance travelled by Micro joule from miles to kilometres

L= (358.416* 1.60934)

L = 576.813 km

Thus, the distance travelled by Micro joule is 576.813 km .

4 0

2 years ago