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cricket20 [7]
3 years ago
11

When an ionic bond forms, the atom with the lower ionization energy will be most likely to lose an electron. True False

Chemistry
2 answers:
shtirl [24]3 years ago
6 0
The answer you are looking for should be true.
galina1969 [7]3 years ago
3 0

Actually, the correct answer was true, I took the test and it was right.

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What is the actual yield of a reaction?
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Ben observes how quickly some dry wood is burning in a campfire. Which term best relates to Ben’s observation?
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Answer:

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What quantum number of the hydrogen atom comes closest to giving a 24-nm-diameter electron orbit?
Paraphin [41]

<em>n</em> = 15. A Bohr orbit with <em>n</em> = 15 comes closest to having a 24 nm diameter .

The formula for the radius <em>r</em> of the <em>n</em>th orbital of a hydrogen atom is

<em>r</em> = <em>n</em>^2·<em>a</em>

where

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We can solve this equation to get

<em>n</em> = √ (<em>r</em>/<em>a</em>)

If <em>d</em> = 24 nm, <em>r</em> = 12 nm.

∴ <em>n</em> = √(12 nm/0.0529 nm) = √227 = 15.1

<em>n</em> must be an integer, so <em>n</em> = 15.

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