Using the balanced equation given below, calculate the number of moles of CaBr2 produced in the reaction of 5.0 moles of AlBr3.
____ moles CaBr2
*your answer should be written as X.X
2AlBr3 + 3CaO —> Al2O3 + 3CaBr2
1 answer:
Answer:
7.5 moles of CaBr2 are produced
Explanation:
Based on the equation:
2AlBr3 + 3CaO → Al2O3 + 3CaBr2
<em>2 moles of AlBr3 produce 3 moles of CaBr2 if CaO is in excess.</em>
<em />
Using this ratio: 2 moles AlBr3 / 3 moles CaBr2. 5 moles of AlBr3 produce:
5 moles AlBr3 * (3 moles CaBr2 / 2 moles AlBr3) =
<h3>7.5 moles of CaBr2 are produced</h3>
<em />
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