Adam applies an input force to the pulley as he pulls down to lift the object. As he does this, Adam wonders about how the pulle
1 answer:
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Answer:
G.P.E = 368.3
Explanation:
Given the following data;
Mass = 2.63kg
Height, h = 14.29m
We know that acceleration due to gravity is equal to 9.8m/s²
To find the gravitational potential energy;
Gravitational potential energy (GPE) is an energy possessed by an object or body due to its position above the earth.
Mathematically, gravitational potential energy is given by the formula;
Where;
G.P.E represents potential energy measured in Joules.
m represents the mass of an object.
g represents acceleration due to gravity measured in meters per seconds square.
h represents the height measured in meters.
G.P.E = 368.3
Note: the unit of gravitational potential energy is Joules.
Answer:
The answer to the questions are as follows
a) The magnitude of the force in UV = 512.41 N
b) The five support reaction components are
1. PQ turning moment force about the z axis
2. PQ turning moment force about the y axis
3. UV turning moment force about the y axis
4. UV turning moment force about the z axis
5. UV turning moment force about the x axis
Please see below
Explanation:
When the system is in 3D equilibrium
Sum of forces in x direction = 0
Sum of forces in y direction = 0
Sum of forces in z direction = 0
Also, Sum of moments in x direction = 0
Sum of moments in y direction = 0
Sum of moments in z direction = 0
From the diagram, we have force in the +ve x direction = 600 N
Also moment about y = 600×0.08 = 48 Nm
Moment about z = 600×0.09 = -54 Nm
Moment about x, = 0 Nm
For the support S, taking moment about x = 0.05 × S
taking moment about y = 0
taking moment about z = 0
At point U, taking moment about y = -0.1U
moment about x = -0.05U
moment about z = -0.1U
Summing the moments we have
In the x, y and z directions
0 + 0.04Vy-1.46Vz -0.05Uz= 0.... (1)
48 + 0.1Vz-0.04Vx - 0.1Uz = 0... (2)
-24 + 0.146Vx-0.1Vy + 0.05Ux + 0.01Uy = 0.... (3)
Ux + Vx = 600 ....(4)
Uy = -Vy .....(5)
Uz = -Vz .......(6)
Solving the above 6 equations we get the following values
Ux = 242.28 N
Uy = -366.74
Uz = -10.40
Vx = 357.72N
Vy = 366.74N
Vz = 10.40N
The magnitude of the force in UV = = 512.41 N
b) The five support reaction components are
1. PQ turning moment force about the z axis
2. PQ turning moment force about the y axis
3. UV turning moment force about the y axis
4. UV turning moment force about the z axis
5. UV turning moment force about the x axis