A voltage of 12 cos(I000t+45) Vis applied to a circuit in which a resistor of 4 .n, aninductor of L H, and a capacitor of 100 μF
1 answer:
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Answer:
magnitude=34.45 m
direction=
Explanation:
Assuming the initial point P1 of this vector is at the origin:
P1=(X1,Y1)=(0,0)
And knowing the other point is P2=(X2,Y2)=(19.5,28.4)
We can find the magnitude and direction of this vector, taking into account a vector has a initial and a final point, with an x-component and a y-component.
For the magnitude we will use the formula to calculate the distance between two points:
(1)
(2)
(3)
(4) This is the magnitude of the vector
For the direction, which is the measure of the angle the vector makes with a horizontal line, we will use the following formula:
(5)
(6)
(7)
Finding :
(8)
(9) This is the direction of the vector
Answer:
<em>An average net force of 5200 N is needed to stop the car</em>
Explanation:
<u>Cinematics and Dynamics</u>
Cinematics describes the variables involved in the movement without dealing with its causes. There are four main concepts in cinematics: Velocity (or its scalar equivalent, the speed), acceleration, time, and displacement (or the scalar equivalent, distance).
The acceleration can be calculated by:
The initial speed is vo=28 m/s, it stops (vf=0) in t=10.5 seconds, thus the acceleration is:
The acceleration is negative because the car loses speed.
Knowing the mass of the car m=1950 Kg, we can calculate the net force required to stop the car by using the formula:
F = m.a =1950*2.67
F = 5200 N
An average net force of 5200 N is needed to stop the car
Answer:
300 N
Explanation:
The net force acting on the arrow is given by Newton's Second Law:
where
m = 0.06 kg is the mass of the arrow
a = 5,000 m/s^2 is the acceleration of the arrow
Substituting the numbers into the equation, we find