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dexar [7]
3 years ago
9

What element has 5 valence electrons and is in period 3.

Physics
1 answer:
Maru [420]3 years ago
5 0

Answer:

Phosphorous

Explanation:

it is the fifth element from the left and it is in the third period so it has 5 valence electrons

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A child is sliding down a slide at the playgound. is mechanicalenergy conserved
Flauer [41]

No. Mechanical energy is not conserved.  There's quite a bit of friction on the slide.  So some of the potential energy is lost to heat on the way down, and the child arrives at the bottom with hot pants and less kinetic energy than you might expect.

5 0
3 years ago
A thin double convex glass lens with an index of 1.56 while surrounded by air has a 10 cm focal length. If it is placed under wa
bearhunter [10]

Explanation:

Formula which holds true for a leans with radii R_{1} and R_{2} and index refraction n is given as follows.

          \frac{1}{f} = (n - 1) [\frac{1}{R_{1}} - \frac{1}{R_{2}}]

Since, the lens is immersed in liquid with index of refraction n_{1}. Therefore, focal length obeys the following.  

            \frac{1}{f_{1}} = \frac{n - n_{1}}{n_{1}} [\frac{1}{R_{1}} - \frac{1}{R_{2}}]  

             \frac{1}{f(n - 1)} = [\frac{1}{R_{1}} - \frac{1}{R_{2}}]

and,       \frac{n_{1}}{f(n - n_{1})} = \frac{1}{R_{1}} - \frac{1}{R_{2}}

or,          f_{1} = \frac{fn_{1}(n - 1)}{(n - n_{1})}

              f_{w} = \frac{10 \times 1.33 \times (1.56 - 1)}{(1.56 - 1.33)}

                          = 32.4 cm

Using thin lens equation, we will find the focal length as follows.

             \frac{1}{f} = \frac{1}{s_{o}} + \frac{1}{s_{i}}

Hence, image distance can be calculated as follows.

       \frac{1}{s_{i}} = \frac{1}{f} - \frac{1}{s_{o}} = \frac{s_{o} - f}{fs_{o}}

              s_{i} = \frac{fs_{o}}{s_{o} - f}

             s_{i} = \frac{32.4 \times 100}{100 - 32.4}

                       = 47.9 cm

Therefore, we can conclude that the focal length of the lens in water is 47.9 cm.

4 0
3 years ago
Which law of motion accounts for the following statement?
strojnjashka [21]
I know that its not the second law. I'm almost positive its the first one. Please let me know if I'm wrong. This sentence makes no sense when you put it with the third law. So, the first law is my guess...
3 0
3 years ago
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Janelle wants to buy some strings of decorative lights for her home. She is trying to decide between two strings of lights that
inysia [295]
If she has a choice and the wiring details are stated on the packaging,
then Janelle should look for lights that are wired in parallel within the
string, and she should avoid lights that are wired in series within the string. 

If a single light in a parallel string fails, then only that one goes out. 
The rest of the lights in the string continue to shimmer and glimmer.

If a single light in a series string fails, then ALL of the lights in that string
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6 0
3 years ago
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Suppose that a baseball is tossed up into the air at an initial velocity 1818​​\text{ m/s} m/s​. The height of the baseball at t
olga2289 [7]

Answer:

13.1 m/s

Explanation:

Given that a baseball is tossed up into the air at an initial velocity 18 m/s​. The height of the baseball at time t​ in seconds is given by h(t) = 18t−4.9t 2 ​​​​​ (in meters).

a) What is the average velocity for [1,1.5]​?

To calculate the velocity travelled by the ball, differentiate the function.

dh/dt = 18 - 9.8t

Substitute t for 1 in the above Differential function

dh/dt = 18 - 9.8 (1)

But dh/dt = velocity

V = 18 - 9.8

V = 8.2 m/s

Average velocity = ( U + V ) / 2

Average velocity = (18 + 8.2)/2

Average velocity = 26.2/2

Average velocity = 13.1 m/s

5 0
3 years ago
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