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3 years ago

All organisms have adaptations. The list below describes how different adaptations might affect different species.

Physics

2 answers:

Airida [17]3 years ago

4 0

Hello. You forgot to enter the answer options. The options are:

"A)Adaptations increase the probability of an organism surviving and reproducing in a specific environment. B)Sudden environmental changes are always necessary for the development of new adaptations. C)The inherited characteristics of a species change over time based on the use or disuse of particular characteristics. D)Adaptations allow individual organisms to change their structures based on environmental conditions."

Answer:

A)Adaptations increase the probability of an organism surviving and reproducing in a specific environment.

Explanation:

The adaptations of living beings do not occur by chance, much less occurred overnight. Throughout the evolutionary process, some organisms have undergone transformations that have given them greater chances of survival in the environment, adjusting morphologically and physiologically to the ecosystem in which they live.

To these transformations, selected by the environment and caused by mutations, we call adaptation, related to the defense mechanism, reproduction, locomotion, food and unfavorable weather conditions.

VMariaS [17]3 years ago

3 0

I think A, because rodents already live in winter months when little food is available, but I'm not sure.

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A thin layer of liquid methylene iodide (n = 1.756) is sandwiched between two flat, parallel plates of glass (n = 1.50). What mu

Harrizon [31]

Answer:

t = 96.1 nm

Explanation:

For strong reflection through liquid layer we know that the path difference between two reflected light rays must be integral multiple of wavelength

now we know that the path difference of two reflected light from thin liquid layer is given as

$2\mu t - \frac{\lambda}{2} = N\lambda$

here we know that

$\mu = 1.756$

t = thickness of layer

N = 0 (for minimum thickness of layer)

$\lambda = 675 nm$

now we have

$2(1.756) t = \frac{675 nm}{2}$

$t = 96.1 nm$

5 0

3 years ago

Two double bonds means that the total number of electrons being shared in the molecule is

Tema [17]

Answer:

9 terms. In carbon dioxide (CO2), there are two oxygen atoms for each carbon atom. Each oxygen atom forms a double bond with carbon, so the molecule is formed by two double bonds. Two double bonds means that the total number of electrons being shared in the molecule is.

Explanation:

3 0

2 years ago

Use the drop-down menus to complete the statement.

Nikitich [7]

Classics.

Resistance is equal to relation between voltage and current.

$R = \frac{U}{I}$

If we express current:

$I = \frac{U}{R}$

If current is in fact 0 then one of the quantities either voltage or resistance must be equal to zero. Since resistance cannot be equal 0, because that would violate mathematical law that states that division by zero is undefined the only logical conclusion is voltage.

So the answer should be C voltage and B zero.

Hope this helps!

8 0

3 years ago

Read 2 more answers

What is the smallest radius of an unbanked (flat) track around which a bicyclist can travel if her speed is 29.5 km/h and the μs

Yakvenalex [24]

Answer:

Radius=15.773 m

Explanation:

Given data

v=29.5 km/h=8.2 m/s

μs=0.435

To find

Radius R

Solution

The acceleration is a centripetal acceleration which is experienced by the bicycle given by

$a=v^{2}/R$

This acceleration is only due to static force which given as

$f=ma\\f=m(v^{2}/R )$

The maximum value of the static force is given as

$Fs_{max}=u_{s}F_{N}$

where

FN is normal force equal to mass*gravity

Therefore when the car is on the verge of sliding

$f=fs_{max}\\ m(v^{2}/R )=u_{s}mg$

Therefore the minimum radius should be found by the bicycle move without sliding

$v^{2}/R=u_{s}g\\ R=v^{2}/u_{s}g\\R=(8.2)^{2}/(0.435*9.8)\\R=15.773m$

8 0

3 years ago

Experimenting with free fall, Mariana observes that her baseball takes 1.5 s to travel the last 30m before hitting the ground. F

Art [367]

Answer:

37.8 m

Explanation:

At point 0, the ball is at height y₀.

At point 1, the ball is at height 30 m.

At point 2, the ball is at height 0 m.

Given:

y₁ = 30 m

y₂ = 0 m

v₀ = 0 m/s

a = -10 m/s²

t₂ − t₁ = 1.5 s

Find: y₀

Use constant acceleration equation.

y = y₀ + v₀ t + ½ at²

Evaluate at point 1.

y₁ = y₀ + v₀ t₁ + ½ at₁²

30 m = y₀ + (0 m/s) t₁ + ½ (-10 m/s²) t₁²

30 = y₀ − 5t₁²

Evaluate at point 2.

y₂ = y₀ + v₀ t₂ + ½ at₂²

0 m = y₀ + (0 m/s) t₂ + ½ (-10 m/s²) t₂²

0 = y₀ − 5t₂²

y₀ = 5t₂²

Substitute:

y₀ = 5 (1.5 + t₁)²

y₀ = 5 (2.25 + 3t₁ + t₁²)

y₀ = 11.25 + 15t₁ + 5t₁²

30 = 11.25 + 15t₁ + 5t₁² − 5t₁²

30 = 11.25 + 15t₁

t₁ = 1.25

30 = y₀ − 5t₁²

30 = y₀ − 5(1.25)²

y₀ ≈ 37.8

4 0

3 years ago