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Leviafan [203]
3 years ago
11

All organisms have adaptations. The list below describes how different adaptations might affect different species.

Physics
2 answers:
Airida [17]3 years ago
4 0

Hello. You forgot to enter the answer options. The options are:

"A)Adaptations increase the probability of an organism surviving and reproducing in a specific environment.  B)Sudden environmental changes are always necessary for the development of new adaptations.  C)The inherited characteristics of a species change over time based on the use or disuse of particular characteristics.  D)Adaptations allow individual organisms to change their structures based on environmental conditions."

Answer:

A)Adaptations increase the probability of an organism surviving and reproducing in a specific environment.  

Explanation:

The adaptations of living beings do not occur by chance, much less occurred overnight. Throughout the evolutionary process, some organisms have undergone transformations that have given them greater chances of survival in the environment, adjusting morphologically and physiologically to the ecosystem in which they live.

To these transformations, selected by the environment and caused by mutations, we call adaptation, related to the defense mechanism, reproduction, locomotion, food and unfavorable weather conditions.

VMariaS [17]3 years ago
3 0
I think A, because rodents already live in winter months when little food is available, but I'm not sure.
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2 years ago
Three identical very dense masses of 3500 kg each are placed on the x axis. One mass is at x1 = -100 cm , one is at the origin,
larisa86 [58]

Answer:

<em>A) 7.37 x 10^-4 N</em>

<em>B) The resultant force will be towards the -x axis</em>

Explanation:

The three masses have mass = 3500 kg

For the force of attraction between the mass at the origin and the mass -100 cm away:

distance r = 100 cm = 1 m

gravitational constant G= 6.67×10^−11 N⋅m^2/kg^2

Gravitational force of attraction F_{g} = \frac{Gm^{2} }{r^{2} }

where G is the gravitational constant

m is the mass of each of the masses

r is the distance apart = 1 m

substituting, we have

F_{g} = \frac{6.67*10^{-11}*3500^{2} }{1^{2} } = 8.17 x 10^-4 N

For the force of attraction between the mass at the origin and the mass 320 cm away

distance r = 320 cm = 3.2 m

F_{g} = \frac{Gm^{2} }{r^{2} }

substituting, we have

F_{g} = \frac{6.67*10^{-11}*3500^{2} }{3.2^{2} } = 7.98 x 10^-5 N

Resultant force = (8.17 x 10^-4 N) - (7.98 x 10^-5 N) = <em>7.37 x 10^-4 N</em>

<em></em>

<em>B) The resultant force will be towards the -x axis</em>

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3 years ago
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