Answer:
Explanation:
Magnetic field due to circular wire at the center = μ₀ I / 2 r
I is current and r is radius . μ₀ = 4π x 10⁻⁷.
field B₁ due to inner loop
B₁ = 4π x 10⁻⁷ x 12 / 2 x .20
= 376.8 x 10⁻⁷
Field due to outer loop
B₂ = 4π x 10⁻⁷ x I / 2 x .30
For equilibrium
B₁ = B₂
376.8 x 10⁻⁷ = 4π x 10⁻⁷ x I / 2 x .30
I = 18 A.
The direction should be opposite to that in the inner wire . It should be anti-clockwise.
This question is false because it is not hot or cold every single day
Answer:
r₂/r₁ = 1.82
Explanation:
The electric field due to a point charge, has the following expression:

For a distance r₁, the magnitude of the electric field is 395 N/C, so we can solve for r₁², as follows:
r₁² =
(1)
For a distance r2, the magnitude of the electric field is 119 N/C, so we can solve for r₂², as follows:
r₂² = 
We can find the quotient r₂/r₁, from (1) and (2):
r₂/r₁ =
= 1.82
Answer:
The average gauge pressure inside the vein is 110270.58 Pa
Explanation:
This question can be solved using the Bernoulli's Equation. First, in order to determine the outlet pressure of the needle, we need to find the total pressure exerted by the atmosphere and the fluid.

Then, we have to find the fluid's outlet velocity with the transversal area of the needle, as follows:

As we have all the information, we can complete the Bernoulli's expression and solve to find the outlet pressure as follows:

Answer:
a.The 60 km/HR car
Explanation:
Kinetic Energy: This can be defined as the energy of a body due to motion. The S.I unit of kinetic energy is Joules (J).
It can be expressed mathematically as
Ek = 1/2mv²......................... Equation 1
Where Ek = kinetic energy, m = mass, v = velocity.
(i) A car travelling at 30 km/hr, with a mass of m,
Ek = 1/2(m)(30)²
Ek = 450m J.
(ii) A car travelling at 60 km/hr, with a mass of m/2
Ek = 1/2(m/2)(60)²
Ek = 900m J.
Thus , the car travelling at 60 km/hr at half mass has a greater kinetic energy to the car traveling at 30 km/hr at full mass.
The right option is a.The 60 km/HR car