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3 years ago

What happens to the particles in a berry sauce mixture as it boils?

Chemistry

1 answer:

lys-0071 [83]3 years ago

8 0

Answer:

The particles garner more and more energy as the boiling continues and thus the energy particles would find a way to escape from it's surface and ultimately the sauce will get to a point where it will turn to gas.

Explanation:

When berry sauce is boiling, it's particles will garner more energy and therefore will move at an increasing faster rate which makes the sauce to continuously expand. Now, the hotter the boiling gets, the more the most energetic particles located at the surface of the sauce will escape from the surface of the sauce. This is because liquids usually evaporate faster when they undergo heating and more particles will have sufficient energy to break away.

As boiling continues, it will get to a point that even particles in the middle of the sauce will begin to form bubbles of gas and at this point, the sauce would have achieved sufficient heat that it will begin to turn to gas.

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Which of these is an element?

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Answer:

Carbon is the only element.

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find the molecular formula of the alkane represented in the mass spectrum. a mass spectrum. the peak at mass 100 has an 8% relat

STatiana [176]

Answer: the molecular altatude of the supercalifragilistic gene should expand by 100%,

Explanation:

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1 year ago

How many atoms are in KOH?

Nata [24]

Answer:

KOH contains only one K, so a mole of KOH contains one mole of K. How many atoms of K are in 1 mole of KOH? There are 6.022 × 1023 atoms of potassium in every mole of potassium. Since one mole of KOH contains one mole of K, the answer is 6.022×1023 atoms of K.

Explanation:

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3 years ago

50.0 mL of 0.200 M HNO2 is titrated to its equivalence point with 1.00 M NaOH. What is the pH at the equivalence point?

yKpoI14uk [10]

Answer:

8.279

Explanation:

The pH can be determined by hydrolysis of a conjugate base of weak acid at the equivalence point.

At the equivalence point, we have

$n_{NaOH}=n_{HNO_2}$

= 25.00 x 0.200

= 5.00 m-mol

= 0.005 mol

Volume of the base that is added to reach the equivalence point is

$\frac{0.005}{1.00} \times 1000= 5.00 \ mL$

Number of moles of $NO^-_{2}=n_{HNO_2}$

= 0.005 mol

Volume at the equivalence point is 25 + 5 = 30.00 mL

Therefore, concentration of $NO^-_{2}= \frac{5}{30}$

= 0.167 M

Now the ICE table :

$NO^-_2 + H_2O \rightarrow HNO_3 + OH^-$

I (M) 0.167 0 0

C (M) -x +x +x

E (M) 0.167-x x x

Now, the value of the base dissociation constant is ,

$K_w=K_a \times K_b$ $(K_w \text{ is the ionic product of water })$

$K_b =\frac{K_w}{K_a}$

$K_b =\frac{1 \times 10^{-14}}{4.6 \times 10^{-4}}$

= $2.174 \times 10^{-11}$

Base ionization constant, $K_b = \frac{\left[HNO_2\right] \left[OH^- \right]}{\left[NO^-_2 \right]}$

$2.174 \times 10^{-11}=\frac{x^2}{0.167 -x}$

$x= 1.9054 \times 10^{-6}$

So, $[OH^-]=1.9054 \times 10^{-6 } \ M$

pOH =- $\log[OH^-]$

= $- \log(1.9054 \times 10^{-6} \ M)$

=5.72

Now, since pH + pOH = 14

pH = 14.00 - 5.72

= 8.279

Therefore the ph is 8.279 at the end of the titration.

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3 years ago

Which of the following molecules experience dipole-dipole forces as its strongest IMF? A) H2 B) SO2 C) NH3 D) CF4 E) BCl3

Xelga [282]

Answer: $NH_3$

Explanation:

a) $H_2$ : This is a non polar covalent compound which are held by weak vanderwaal forces of attraction.

b) $SO_2$ : This is a covalent compound which is polar due to the presence of lone pair of electrons and are held by dipole-dipole forces of attraction.

c) $NH_3$ : These are joined by a special type of dipole dipole attraction called as hydrogen bond. It forms between electronegative nitrogen atom and hydrogen atom and is the strongest interaction.

d) $CF_4$ : This is a covalent compound and is non polar which are held by weak vanderwaal forces of attraction.

e) $BCl_3$ : This is a covalent compound and is non polar which are held by weak vander waal forces of attraction.

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3 years ago