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devlian [24]
2 years ago
9

What is the equations that decompose hydrogen peroxide

Chemistry
1 answer:
Rufina [12.5K]2 years ago
5 0
2H2O2 decomposes into the products 2H2O + O2(g)
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A gas sample has a temperature of 19 °C with an unknown volume. The
andreev551 [17]

Answer: 373 mL

Explanation:

Since there is no change in pressure, the formula: V / T = V / T can be used.

However, you must first convert the temperatures to Kelvin by adding 273 to them:

(19 + 273) = 292K and (90 + 273) = 363K.

Now, plug in: V / 292 = 464 / 363 → V = 373 mL :)

4 0
2 years ago
PLZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZ
malfutka [58]

Answer: I think G.

Explanation:

8 0
3 years ago
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What is the representative particle for barium chloride?
KIM [24]
Barium chloride is salt with ionic bonds. Barium chloride contains one barium cations (charge of ion is 2+) and two chlorine anions (charge for ion is 1-).
The representative particle<span> of an ionic compound is its formula unit (</span>lowest whole number ratio of ions in an ionic compound), for barium chloride that is BaCl₂.
8 0
3 years ago
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Science question down below
aliya0001 [1]
Option 1/A (It is the first one)
6 0
3 years ago
At a certain temperature the vapor pressure of pure acetic acid HCH3CO2 is measured to be 226.torr. Suppose a solution is prepar
Rudiy27

Answer:

The partial pressure of acetic acid is 73.5 torr

Explanation:

Step 1: Data given

Total pressure is 226 torr

mass of acetic acid = 126 grams

mass of methanol = 141 grams

 

Step 2: Calculate moles of acetic acid

moles acetic acid = mass acetic acid / molar mass acetic acid

moles acetic acid = 127 grams / 60.05 g/mol

moles acetic acid = 2.115 moles

Step 3: Calculate moles of methanol

moles methanol = 141 grams / 32.04 g/mol

moles methanol = 4.40 moles

Step 4: Calculate total moles

Total moles = moles of acetic acid + moles methanol

Total moles = 2.115 moles + 4.40 moles

Total moles = 6.515 moles

Step 5: Calculate mole fraction of acetic acid

2.115 moles / 6.515 moles = 0.325

Step 6: Calculate partial pressure of acetic acid

P(acetic acid) = 0.325 * 226

P(acetic acid) = 73.45 torr ≈73.5

 

We can control this by calculating the partial pressure of methanol

mole fraction of methanol = (6.515-2.115)/6.515 = 0.675

P(methanol) = 0.675 * 226 = 152.55

226 - 152.55 = 73.45 torr  

The partial pressure of acetic acid is 73.5 torr

4 0
3 years ago
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