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andriy [413]
3 years ago
12

Help me I need this now

Physics
1 answer:
9966 [12]3 years ago
4 0

Answer:

If the height of the ramp is changed at a different height then the  speed of the car will change.

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Select the correct answer
Sergeu [11.5K]

Answer:

I may be a little late, but it's A i got it right on the exam

Explanation:

5 0
3 years ago
A 1250 kg car is pulling a 325 kb trailer. The car and trailer have an acceleration of 2,15m/sec2 together. Determine the net fo
xenn [34]

To solve this problem we will apply the definition of Newton's second law, which says that force is equivalent to body mass by acceleration. In this case the mass of the trailer is 325Kg and its acceleration is 2.15m / s ^ 2, so we will proceed to replace and multiply these values to find the net force on this object.

F= ma

F= (325 kg)(2.15 m/s^2)

F= 698.75N

Under the reference system in which the direction of travel is the positive direction, the direction of the force will be positive.

7 0
3 years ago
Which of the following is an arithmetic sequence? A. 2, 1, 4, 3, 6, 5, …
sergey [27]

Explanation:

it is not a arithmetic sequence

6 0
2 years ago
Which force acts as an object to move it from rest or a constant straight line motion
sleet_krkn [62]

Answer:

The force is Inertia

Explanation:

The force that acts on an object to move it from rest or a constant straight line motion is known as Inertia.

In physics the above statement is governed by Newton's first law of motion which is also known as Law of Inertia.

This law states that, an object that is at rest will remain at rest and an object that is moving will continue to move in a straight line with constant speed, if and only if the net force acting on the object is zero.

This implies that, A stationary object will remain motionless if no force acts on it while a object with constant velocity will continue moving with constant velocity until a force acts on it (neglecting resistance from air and friction).

8 0
3 years ago
Read 2 more answers
The barometer of a mountain hiker reads 930 mbars at the beginning of a hiking trip and 780 mbars at the end. Neglecting the eff
lara31 [8.8K]
We could use the change of pressure to calculate for the height climbed by the mountain hiker. The change of pressure is given by

p = rho * g * h, where p is the change of pressure, rho is the air density, g is the acceleration due to gravity, and h is the height.

Using the conversion 1 mbar = 100 Pa,

(930 - 780)(100) = (1.20)(9.80)h
15000 = 1.20*9.80*h

h = 1.28 km
6 0
3 years ago
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