Answer:
Q = 47.06 degrees
Explanation:
Given:
- The transmitted intensity I = 0.464 I_o
- Incident Intensity I = I_o
Find:
What angle should the principle axis make with respect to the incident polarization
Solution:
- The relation of transmitted Intensity I to to the incident intensity I_o on a plane paper with its principle axis is given by:
I = I_o * cos^2 (Q)
- Where Q is the angle between the Incident polarized Light and its angle with the principle axis. Hence, Using the relation given above:
Q = cos ^-1 (sqrt (I / I_o))
- Plug the values in:
Q = cos^-1 ( sqrt (0.464))
Q = cos^-1 (0.6811754546)
Q = 47.06 degrees
Answer:
C. crust, mantle, core
Explanation:
density increases as you travel from the crust to the inner core
the crust is on top
next is the mantle
and then the core
Answer:
a) 4.04*10^-12m
b) 0.0209nm
c) 0.253MeV
Explanation:
The formula for Compton's scattering is given by:

where h is the Planck's constant, m is the mass of the electron and c is the speed of light.
a) by replacing in the formula you obtain the Compton shift:

b) The change in photon energy is given by:

c) The electron Compton wavelength is 2.43 × 10-12 m. Hence you can use the Broglie's relation to compute the momentum of the electron and then the kinetic energy.


Answer:
Explanation:
Let us calculate gallon used in one hour .
It travels 70 miles in one hour
in 70 miles it uses 70 / 34 gallons of fuel
70 / 34 gallons = 70 / 34 x 3.7854 kg
= 7.8 kg
heat generated = 7.8 x 44 x 10⁶ J
= 343.2 x 10⁶ J
This is heat generated in one hour
heat generated in one second = 343.2 x 10⁶ / 60 x 60 J/s
= 95.33 x 10³ J /s
= 95.33 kW.