A) The magnitude of the electric field generated by a single point charge is given by

where k is the Coulomb's constant, q is the charge and r is the distance at which we calculate the field.
Since we want to know the intensity of the field at distance of r=4.52 m from the charge of q=8.15 C, the intensity of the electric field is

b) Direction of the field
The charge that produces the field is negative, and we know that the electric field generated by a negative charge points toward the charge. Therefore, the direction of the electric field is towards the charge.
Given that:
Mass (m) = 20 g = 0.02 Kg,
temperature (T₁) = -10°C = -10+273 = 263 K
temperature (T₂) = 10°C = 10+273 = 283 K
Specific heat of water (Cp) = 4.187 KJ/Kg k
We know that Heat transfer (Q) = m. Cp.( T₂ - T₁)
= 0.02 × 4.187 × (283-263)
<em> Q = 1.67 KJ</em>
<em>Heat transferred is 1.67 KJ</em>
As you illustrate the problem, you may come up with the same diagram as the one shown in the attached picture. The relative velocity is the linear velocity between the two velocities. This is calculated by simply finding the difference of their velocities. Since, the velocity is with respect to Jane relative to Mary, the solution is as follows:
Relative velocity = Velocity of Jane - Velocity of Mary
Relative Velocity = 4.67 m/s - 3.59 m/s =
1.08 m/s
The child's linear speed is
<em> (pi / 5) x (the child's distance from the center of the ride, in feet)</em>
feet per second.