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Artist 52 [7]
3 years ago
10

The presence of intermolecular forces in liquids is observed through several different phenomena. Match each of below statement

with its corresponding option.
adhesion, surface tension, capillary action, cohesion, meniscus, viscosity.1. _____ the ability of a liquid to flow up a narrow tube unassisted against gravity.2. _____ the attraction between molecules of the same substance.3. _____ the curvature of the surface of a liquid at the interface with the container.4. _____ the attraction between dissimilar molecules.5. _____ the resistance of a liquid to flow.6. _____ the elasticity of the surface layer of a liquid due to the liquid trying to minimize its surface area.
Options:
a. adhesion,
b. surface tension,
c. capillary action,
d. cohesion,
e. meniscus,
f. viscosity.
Chemistry
1 answer:
Stels [109]3 years ago
4 0

Answer:

1) Capillary action

2) Cohesion

3)Miniscus

4) Adhesion

5) Viscousity

6) Surface tension

Explanation:

Intermolecular forces are forces that holds molecules together in liquid, these is possible by inter-molecular interactions that exist within the liquids.these forces includes forces such as Waals forces and hydrogen bonds.

When there is great inter-molecular forces, there will be high freezing point and boiling point . At a lower inter-molecular forces the boiling point becomes low too,which brings about great fluidity of the liquid. The liquid flow reluctantly where greater force exist in the liquid. Some of those factors used in characterizing which are;

1)adhesion,

2) surface tension,

3)capillary action,

4)cohesion,

5) meniscus,

6)viscosity.

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When molten candle wax solidifies is that a chemical reaction or not?l
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<u>Explanation:</u>

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3 years ago
0.820 L has a mass of 2.56kg what is the density of this liquid in kg/L
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8 0
3 years ago
What is the molar mass of magnesium hydroxide
leonid [27]
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7 0
3 years ago
Read 2 more answers
PLEASE HELP ASAP!!!!
Vsevolod [243]

Answer:

The answer to your question is  C = 0.037 cal/g°C

Explanation:

Data

mass of the wire = m = 237 g

temperature 1 = T1 = 25°C

temperature 2 = T2 = 107°C

Heat = Q = 722 cal

Specific heat = C

Process

1.- Write the formula to find the specific heat

            Q = mC(T2 - T1)

-Solve for C

            C = Q / m(T2 - T1)

2.- Substitution

             C = 722 / 237(107 - 25)

3.- Simplification

              C = 722 / 237(82)

              C = 722 / 19434

4.- Result

               C = 0.037 cal/g°C

4 0
3 years ago
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