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3 years ago

Identify the spectator ions in this reaction. Check all that apply.

Chemistry

2 answers:

balandron [24]3 years ago

4 0

CN, LI are the only two

lutik1710 [3]3 years ago

4 0

Answer: The spectator ions are $CN^-\text{ and }Li^+$

Explanation:

Spectator ions are defined as the ions which does not get involved in a chemical equation or they are ions which are found on both the sides of the chemical reaction present in ionic form.

The given chemical equation is:

$H^++CN^-+Li^++OH^-\rightarrow Li^++CN^-+H_2O$

The ions which are present on both the sides of the equation are lithium and cynaide ions.

Hence, the correct answer are $CN^-\text{ and }Li^+$

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He following balanced equation shows the formation of water. 2H2 + O2 mc020-1.jpg 2H2O How many moles of oxygen (O2) are require

mrs_skeptik [129]

Answer : The correct option is, 13.7 mole

Solution : Given,

Moles of $H_2$ = 27.4 moles

The given balanced chemical reaction is,

$2H_2+O_2\rightarrow 2H_2O$

From the balanced chemical reaction, we conclude that

As, 2 moles of $H_2$ react with 1 moles of $O_2$

So, 27.4 moles of $H_2$ react with $\frac{27.4}{2}=13.7$ moles of $O_2$

Therefore, the number of moles of oxygen $O_2$ required are, 13.7 moles

7 0

2 years ago

Read 2 more answers

I have a question about ionization energy.

ValentinkaMS [17]

Ionization energy is the measure of the extend to which the nucleus attracts the outermost electron
if ionization energy us high than force of attraction Is high so it is not easy to remove and vice versa .
hope you understand.....

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3 years ago

52° 31' 12.0288"N and 13° 24' 17.8344" E. What continent is it on?

olga55 [171]

Answer: Europe

Explanation: it’s in germany

7 0

2 years ago

Calculate the mass of Octane needed to release 6.20 mol Co2

n200080 [17]

The combustion reaction of octane is as follow,

C₈H₁₈ + 25/2 O₂ → 8 CO₂ + 9 H₂O

According to balance equation,

8 moles of CO₂ are released when = 114.23 g (1 mole) Octane is reacted

So,

6.20 moles of CO₂ will release when = X g of Octane is reacted

Solving for X,
X = (114.23 g × 6.20 mol) ÷ 8 mol

X = 88.52 g of Octane
Result:
88.52 g of Octane is needed to release 6.20 mol CO₂.

8 0

2 years ago

What is the molarity of a solution in which 175.8 grams of NaCl is dissolved in 1.5 L of water?

Sophie [7]

175.8 g NaCl to moles:
(175.8 g)/(58.44 g/mol) = 3.008 mol NaCl

Molarity = moles of solute/volume of solution in liters

(3.008 mol NaCl)/(1.5 L) = 2.0 M.

The molarity of this solution would be 2.0 M.

8 0

2 years ago