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3 years ago

Identify the spectator ions in this reaction. Check all that apply.

Chemistry

2 answers:

balandron [24]3 years ago

4 0

CN, LI are the only two

lutik1710 [3]3 years ago

4 0

Answer: The spectator ions are $CN^-\text{ and }Li^+$

Explanation:

Spectator ions are defined as the ions which does not get involved in a chemical equation or they are ions which are found on both the sides of the chemical reaction present in ionic form.

The given chemical equation is:

$H^++CN^-+Li^++OH^-\rightarrow Li^++CN^-+H_2O$

The ions which are present on both the sides of the equation are lithium and cynaide ions.

Hence, the correct answer are $CN^-\text{ and }Li^+$

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Answer:

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Explanation:

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3 years ago

What is the atomic number of an atom that has 20 protons and 20 neutrons

vladimir2022 [97]

Answer:

Explanation:

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We need to find the atomic number of an atom that has 20 protons and 20 neutrons

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Since the atom has 20 protons, the atomic number of the said atom is 20

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3 years ago

5. Which pair of elements would combine to forin an ionic compound?

Natasha_Volkova [10]

C.silicon and oxygen is the answer

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3 years ago

When an object is pushed by a force and moves in the direction of the force, work is done on the object. The amount of work equa

lora16 [44]

Explanation:

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3 0

3 years ago

When a compound containing cesium ions is heated in a Bunsen burner flame, photons with an energy of 4.30 x 10-19 J are emitted.

inessss [21]

Answer: The wavelength of the flame is 462 nm and color of cesium flame is blue.

Explanation:

To calculate the wavelength, we use Planck's equation, which is:

$E=\frac{hc}{\lambda}$

where,

E = Energy of 1 photon = $4.30\times 10^{-19}J$

h = Planck's constant = $6.625\times 10^{-34}J.s$

c = speed of light = $3\times 10^8m/s$

$\lambda$ = wavelength = ?

Putting values in above equation, we get:

$4.30\times 10^{-19}=\frac{6.625\times 10^{-34}J.s\times 3\times 10^8m/s}{\lambda }\\\\\lambda=\frac{6.625\times 10^{-34}J.s\times 3\times 10^8m/s}{4.30\times 10^{-19}}=4.62\times 10^{-7}m=462nm$

The range of wavelength of blue light lies in range of 500 nm - 435 nm

The calculated wavelength lies in the above range. So, the color of the cesium flame is 462 nm

Hence, the wavelength of the flame is 462 nm and color of cesium flame is blue.

6 0

3 years ago