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3 years ago

Identify the spectator ions in this reaction. Check all that apply.

Chemistry

2 answers:

balandron [24]3 years ago

4 0

CN, LI are the only two

lutik1710 [3]3 years ago

4 0

Answer: The spectator ions are $CN^-\text{ and }Li^+$

Explanation:

Spectator ions are defined as the ions which does not get involved in a chemical equation or they are ions which are found on both the sides of the chemical reaction present in ionic form.

The given chemical equation is:

$H^++CN^-+Li^++OH^-\rightarrow Li^++CN^-+H_2O$

The ions which are present on both the sides of the equation are lithium and cynaide ions.

Hence, the correct answer are $CN^-\text{ and }Li^+$

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I think it is oxidation number

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Viktor [21]

Answer:

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Explanation:

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Let the order of the reaction be x.

The rate law of the reaction can be written as:

$R=k[H_2O_2]^x$

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$R=-\frac{0.697 M-0.882 M}{60 s-0 s}=0.00308 M/s$

$0.00308 M/s=k[0.697 M]^x$ ..[1]

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$R=-\frac{0.236M-0.372M}{120s-60 s}=0.00227 M/s$

$0.00218 M/s=k[0.236 M]^x$ ..[2]

[1] ÷ [2]

$\frac{0.00308 M/s}{0.00227 M/s}=\frac{k[0.697 M]^x}{k[0.236M]^x}$

Solving fro x:

x = 0.92 ≈ 1

$R=k[H_2O_2]^1$

$0.00308 M/s=k[0.697 M]^1$

$k=\frac{0.00308 M/s}{[0.697 M]^1}=0.00442 s^{-1}$

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4 years ago

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Answer:

Explanation:

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3 years ago

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Answer:

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Explanation:

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k = [NCl₃]² / ( [N₂] * [Cl₂]³)

We are given all the required data from the problem, so now we solve for k:

k = (1.9x10⁻¹)² / ( (1.4x10⁻³) * (4.3x10⁻⁴)³ )

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4 years ago

What is the reactants start for H2 + O2 --> H2O

zaharov [31]

Answer:

H2 + O2

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7 0

3 years ago

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