A mass ofm= 0.7 kg hung vertically fromthis spring stretches the spring 0.1 m.The acceleration of gravity is 9.8 m/s2.Calculate
1 answer:
Answer:
Spring constant of the spring will be 68.6 N/m
Explanation:
It is given mass which is vertically hung m = 6.80 kg
Spring is stretched by length of 0.1 m , so x = 0.210 m
Acceleration due to gravity will be equal to
Force on the mass which is vertically hung will be equal to mg
This force will be balanced by spring force acting on the mass
And spring force is equal to F = Kx
So kx = mg
k = 68.6 N /m
So spring constant of the spring will be equal to 68.6 N/m
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