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Free_Kalibri [48]
3 years ago
7

An ion accelerated through a potential difference of 115 V experiences an increase in kinetic energy of 7.37 x 1017 J. Calculate

the charge on the ion.
Physics
1 answer:
riadik2000 [5.3K]3 years ago
4 0

Answer: 6.408(10)^{-19} C

Explanation:

This problem can be solved by the following equation:

\Delta K=q V

Where:

\Delta K=7.37(10)^{-17} J is the change in kinetic energy

V=115 V is the electric potential difference

q is the electric charge

Finding q:

q=\frac{\Delta K}{V}

q=\frac{7.37(10)^{-17} J}{115 V}

Finally:

q=6.408(10)^{-19} C

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In a large restaurant an average 60% customers ask for water with their meal. A random sample of 10 customers is selected. Find
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Answer:

a)P(6)=0.25

b)p(x

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a)

Generally the probability that exactly 6 ask for water is mathematically given by

P(x)6=10C_6 (0..6)^6(0.4)^{10-6}

P(6)=0.25

b)

Generally the probability that  less than 9 ask for water with meal  is mathematically given by

p(xg)

p(x

p(x

p(x

c)

Generally the probability that  at least 3 ask for water with meal  is mathematically given by

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p(x\geq3)=1-[p(0)+p(1)+p(2)]

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p(x\geq3)=0.9878

d)

Generally the mean and standard deviation of sample size is mathematically given by

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Standard deviation

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