Answer:
3.67 N
Explanation:
From the question given above, the following data were obtained:
Charge of 1st object (q₁) = +15.5 μC
Charge of 2nd object (q₂) = –7.25 μC
Distance apart (r) = 0.525 m
Force (F) =?
Next, we shall convert micro coulomb (μC) to coulomb (C). This can be obtained as follow:
For the 1st object
1 μC = 1×10¯⁶ C
Therefore,
15.5 μC = 15.5 × 1×10¯⁶
15.5 μC = 15.5×10¯⁶ C
For the 2nd object:
1 μC = 1×10¯⁶ C
Therefore,
–7.25 μC = –7.25 × 1×10¯⁶
–7.25 μC = –7.25×10¯⁶ C
Finally, we shall determine the force. This can be obtained as follow:
Charge of 1st object (q₁) = +15.5×10¯⁶ C
Charge of 2nd object (q₂) = –7.25×10¯⁶ C
Distance apart (r) = 0.525 m
Electrical constant (K) = 9×10⁹ Nm²/C²
Force (F) =?
F = Kq₁q₂ / r²
F = 9×10⁹ × 15.5×10¯⁶ × 7.25×10¯⁶ / 0.525²
F = 3.67 N
Therefore, the force on the object is 3.67 N
Gravity is a force acting on a object
-- The density of the glass alone doesn't change.
-- The density of the water alone doesn't change.
-- The density of (the entire glass + everything IN IT) increases,
because the part that used to be air (with very low density) is
changed to water (with much higher density than the air had).
Force is directly proportional to mass according to the second law of Newton, meaning that the greater the mass is, bigger the force should be in order to move the object. In this case, Mutt's wagon has a mass two times greater than Jeff's and they have to be equal. So either Jeff must slow down twice as much or Mutt has to speed up twice as much. The only option we can choose according to our reasoning is that Mutt must use twice as much force to push his cart, because his mass is two times bigger. According to me the answer is C).
