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Ganezh [65]
3 years ago
12

When applying Gauss' law for a capacitor containing a dielectric, which of the following statements is false? (Latter part of se

ction 6.)
A) The electric field vector is multiplied by κ, the dielectric constant.
B) The charge enclosed by the Gaussian surface includes both the free charge and the induced surface charges.
C) Gauss' law for a dielectric includes the ability to account for varying dielectric constant over the Gaussian surface.
D) Gauss' law for a dielectric is the most general form of Gauss' law.
E) Gauss' law for a dielectric can be applied to many types of capacitors.
Physics
1 answer:
Irina-Kira [14]3 years ago
3 0

Answer:a

Explanation:

Introducing a dielectric inside a capacitor reduces the Electric field . Charge develops on dielectric such that it is opposite to the corresponding face . For example Positive charge of capacitor induces negative charge on dielectric which will create an Electric Field in opposite direction.

So Electric Field decreased by a factor of \frac{1}{K} where

K=dielectric\ magnitude    

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Complete Question

The complete question is shown on the first uploaded image

Answer:

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Explanation:

From the question we are told that

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W is negative because the working is done on the environment by the system which is indicated by volume increase

     Substituting values

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                    = -1.75 \ L \ \cdot atm

Now  1 \  L \cdot atm = 101.3J

  Therefore  W = -1.75* 101.3

                          = -177.275J

   

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