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Alla [95]
4 years ago
10

When the man inside the treadmill steps up, what force pulls home back? In what direction does this force move him?

Physics
1 answer:
poizon [28]4 years ago
4 0
These image should help you out

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according to newton's law of universal gravitation, in which of the following situations does the gravitational attraction betwe
Alex17521 [72]

Explanation:

The force acting between two masses is given by :

F=G\dfrac{m_1m_2}{d^2}........(1)

Where

G is the universal gravitational constant

m_1\ and\ m_2 are masses

d is the distance between two masses

It is clear from equation (1) that the gravitational attraction between the bodies always increases if the masses of bodies increases and when the separation between masses decreases.

So, the correct answer is "the masses increase, and the distance between the centers of mass decreases". This is because the force of gravitation is directly proportional to the masses and inversely proportional to the separation.

4 0
3 years ago
If the wave represents a sound wave, explain how increasing amplitude will affect the loudness of the sound? If we decrease the
Viktor [21]

Answer:

Explanation:

Think of a sound wave like a wave on the ocean, or lake... It's not really water moving, as much as it's energy moving through the water. Ever see something floating on the water, and notice that it doesn't come in with the wave, but rides over the top and back down into the trough between them? Sound waves are very similar to that. If you looked at a subwoofer speaker being driven at say... 50 cycles a second, you'd actually be able to see the speaker cone moving back and forth. The more power you feed into the speaker, the more it moves back and forth, not more quickly, as that would be a higher frequency, but further in and further out, still at 50 cycles per second. Every time it pushed out, it's compressing the air in front of it... the compressed air moves away from the speaker's cone, but not as a breeze or wind, but as a wave through the air, similar to a wave on the ocean

More power, more amplitude, bigger "wave", louder ( to the human ear) sound.

If you had a big speaker ( subwoofer ) and ran a low frequency signal with enough power in it, you could hold a piece of paper in front of it, and see the piece of paper move in and out at exactly the same frequency as the speaker cone. The farther away from the speaker you got, the less it'd move as the energy of the sound wave dispersed through the room.

Sound is a wave

We hear because our eardrums resonates with this wave I.e. our ear drums will vibrate with the same frequency and amplitude. which is converted to an electrical signal and processed by our brain.

By increasing the amplitude our eardrums also vibrate with a higher amplitude which we experience as a louder sound.

Of course when this amplitude is too high the resulting resonance tears our eardrums so that they can't resonate with the sound wave I.e. we become deaf

6 0
3 years ago
A water balloon is thrown horizontally at a speed of 2.00 m/s from the roof of a building that is 6.00 m above the ground. At th
Elis [28]

Answer:

  • <u>The water ballon that was thrown straight down at 2.00 m/s hits the ground first, 0.19 s before the other ballon.</u>

Explanation:

The motions of the two water ballons are ruled by the kinematic equations:

  • y=y_0+V_0t-gt^2/2

We are only interested in the vertical motion, so that equation is all what you need.

<u>1. Water ballon is thrown horizontally at sped 2.00 m/s.</u>

The time the ballon takes to hit the ground is independent of the horizontal speed.

Since 2.00 m/s is a horizontal speed, you take the initial vertical speed equal to 0.

Then:

y=y_0+V_0t-gt^2/2\\ \\ 0=6.00m-9.8\frac{m}{s^2} t^2/2\\ \\ t=\sqrt{2\times6.00m/9.8\frac{m}{s^2}}\\\\ t=1.11s

<u>2. Water ballon thrown straight down at 2.00 m/s</u>

Now the initial vertical speed is 2.00 m/s down. So, the equation is:

0=6.00m-2.00\frac{m}{s}t-9.8\frac{m}{s^2}t^2/2\\ \\ 4.9t^2+2t-6=0\\ \\ t=0.92s

To solve the equation you can use the quadratic formula.

t=\frac{-2+/-\sqrt{2^2-4(4.9)(-6)} }{2(4.9)}\\ \\ t=-1.33\\ \\ t=0.92

You get two times. One of the times is negative, thus it does not have physical meaning.

<u>3. Conclusion:</u>

The water ballon that was thrown straight down at 2.00 m/s hits the ground first by 1.11 s - 0.92s = 0.19 s.

5 0
3 years ago
Arrange the objects in order from least to greatest potential energy. Assume that gravity is constant. (Use PE = m × g × h.)
yawa3891 [41]

Answer:The objects in order from least to greatest potential energy:

3<1<4<2

Explanation:

1. Potential energy of a 15-kilogram stone  found at a height of  3 meters:

mgh=15 kg\times 9.8 m/s^2\times 3 m=441 J

2. Potential energy 10 kilograms of water  stored at a height of  9 meters:

mgh=10 kg\times 9.8 m/s^2\times 9 m=882 J

3. Potential energy 1-kilogram ball located  20 meters in the air:

mgh=1 kg\times 9.8 m/s^2\times 20 m=196 J

4. Potential energy box of books weighing  25 kilograms placed on  a shelf 2 meters high:

mgh=25 kg\times 9.8 m/s^2\times 2 m=490 J

The objects in order from least to greatest potential energy:

3<1<4<2

8 0
3 years ago
Read 2 more answers
According to the Biot-Savart Force Law and the right hand rule, if a magnetic field is directed rightward (+ x axis) and a posit
julsineya [31]
The direction would go upwards(+yaxis)
6 0
4 years ago
Read 2 more answers
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