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Delicious77 [7]
3 years ago
13

Which best explains why a wood burning fireplace represents an open system

Physics
2 answers:
REY [17]3 years ago
5 0

Answer:

Explanation:

An open system is defined as the a system in which energy or mass can be gained or loss from the environment.

Here in this case a wood burning fireplace represents an open system as it is directly taking oxygen from the atmosphere.

During this direct exchange of gases heat is produced hence mass of wood is lost and oxygen is gained from the atmosphere.

So as fire is required from atmosphere to burn the wood, it best explains why a wood burning represent an open system.

-Dominant- [34]3 years ago
4 0
Because a fire requires oxygen from the atmosphere to burn 
 
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the idling engines of a landing turbojet produce forward thrust when operating in a normal manner, but they can produce reverse
Finger [1]

Forward thrust has positive values and reverse thrust has negative values.

Thrust is a sudden push or pull in a certain direction.

a)

Flight speed u = 150 km/h

1 km/h = \frac{1}{3.6} km/s

therefore, 150 km/h =  41.67 km / s

The thrust force represents the horizontal or x-component of momentum equation:

T = m_{exhaust} * U_{exhaust} - U_{flight}

T = 50 * (150 - 41.67)

T = 5416.67 N

Therefore, the value of forward thrust is 5416.67 N.

b)

Now the exhaust velocity is now vertical due to reverse thrust application, then it has a zero horizontal component,

thus thrust equation is:

T = m_{exhaust} * U_{exhaust} - U_{flight}

T = 50 * (0 - 41.67)

T = -2083.5 N

Therefore, the thrust force T is -2083.5 N in the reverse direction.

c)

Now the exhaust velocity and flight velocity is zero, then it has a zero horizontal component, thus thrust is also zero becauseU_{exhaust} = U_{flight} = 0\\

T = 0

Therefore, there is no difference in two velocities in x direction.

The given question is incomplete, the complete question is,

"The idling engines of a landing turbojet produce forward thrust when operating in a normal manner, but they can produce reverse thrust if the jet is properly deflected. Suppose that while the aircraft rolls down the runway at 150 km/h the idling engine consumes air at 50 kg/s and produces an exhaust velocity of 150 m/s.

a. What is the forward thrust of this engine?

b. What are the magnitude and direction (i.e., forward or reverse) if the exhaust is deflected 90 degree without affecting the mass flow?

c. What are the magnitude and direction of the thrust (forward or reverse) after the plane has come to a stop, with 90 degree exhaust deflection and an airflow of 40 kg/s?"

To know more about thrust,

brainly.com/question/14552836

#SPJ1

3 0
1 year ago
Question 6 (5 points)
Ahat [919]

Answer:

its how life meets water and earth meets air.

Explanation:

4 0
3 years ago
While playing baseball with your friends your hands begin to sting after you ctach several fast balls.
muminat

Answer:

Explanation:

To stop a ball with high momentum in a small-time imparts a high amount of impact on hands. This is the reason for the stinging of hands.

The momentum of the ball is due to the mass and velocity. To prevent stinging in the hand one needs to lower his hands to increase the time of contact. In this way, the momentum transfer to the hands will be lesser.        

7 0
3 years ago
Given: Q1 = +10 uc = 1.0 x 10-5C
ser-zykov [4K]

Answer:

-0.038 N

Explanation:

F=K Q1 Q2/r^2 by COULOMB'S LAW

F= 9×10^9×1×10^-5×-1.5×10^-5/(6)^2

F= -0.038 N

5 0
3 years ago
if a pressure of 70.kPa on a volume of 80.cm cubed is reduced to 10.kPa, by what factor does the pressure change
boyakko [2]

70-10/70 x 100  percentage change ....

60/70, 6/7 fract change


6 0
3 years ago
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