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Lana71 [14]
3 years ago
9

Which of the following is an example of element? A.Water B.Chlorine C.Carbon Dioxide D.Sugar

Chemistry
1 answer:
prisoha [69]3 years ago
8 0
The answer is B chlorine. Chlorine is and elements and the others are compounds.
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What is the percent composition by mass of sulfur in the compound mgso4
Margaret [11]

Answer:

26.7% is the percent composition by mass of sulfur in a compound named magnesium sulfate.

Explanation:

Molar mass of compound = 120 g/mol

Number of sulfur atom = 1

Atomic mass of sulfur = 32 g/mol

Percentage of element in compound :

=\frac{\text{Number of atoms}\times \text{Atomic mass}}{\text{molar mas of compound}}\times 100

Sulfur :

=\frac{1\times 32 g/mol}{120 g/mol}\times 100=26.7\%

26.7% is the percent composition by mass of sulfur in a compound named magnesium sulfate.

6 0
3 years ago
Calculate the speed of a marble that rolls 9 cm in 4 seconds
cupoosta [38]

Answer:

2.25

Explanation:

9/4

6 0
3 years ago
What is the difference between weather and climate? Why is it so hot along the equator? Why are some areas of the ocean warmer t
ziro4ka [17]

Answer:

the weather is raining sunning or rainbow

because of the sun its so hot

because its cold snowing

because the oceans is water you can swimming

Explanation:

that is

3 0
2 years ago
Read 2 more answers
A sample of 0.600 mol of a metal m reacts completely with excess fluorine to form 46.8 g of mf2. how many moles of f are in the
oksian1 [2.3K]
The balanced chemical reaction is expressed as:

M + F2 = MF2

To determine the moles of the element fluorine present in the product, we need to determine the moles of the product formed from the reaction and relate this value to the ratio of the elements in MF2. We do as follows:

moles MF2 produced = 0.600 mol M ( 1 mol MF2 / 1 mol M ) = 0.600 mol MF2
molar mass MF2 = 46.8 g MF2 / 0.6 mol MF2 = 78 g/mol
moles MF2 = 46.8 g ( 1 mol / 78 g ) = 0.6 mol
moles F = 0.6 mol MF2 ( 2 mol F / 1 mol MF2 ) = 1.2 moles F
6 0
3 years ago
A naturally occurring element consists of three isotopes. The data for the isotopes are:
max2010maxim [7]
(46.972* 69.472% + 48.961*21.667% + <span>49.954*8.8610%)/100% =

</span>= 46.972* 0.69472 + 48.961*0.21667 + 49.954*0.088610 =47.667 u
7 0
3 years ago
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