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tamaranim1 [39]
4 years ago
13

Let's practice calculating the frictional force of a skier on old "woody" skis and wet snow. The skier has a mass of 58 kg. The

coefficient of kinetic friction of wood skis on wet snow is 0.1 Notice there are no units for the coefficient of friction. What is the kinetic frictional force between the wood skis and the snow
Physics
1 answer:
kicyunya [14]4 years ago
8 0

Answer:

Kinetic frictional force will be equal to 56.84 N

Explanation:

We have given mass of the skier m = 58 kg

Acceleration due to gravity g=9.8m/sec^2

Coefficient of kinetic friction \mu _k=0.1

We have to find the kinetic frictional force

Kinetic frictional force is given by

F_K=\mu _Kmg=0.1\times 58\times 9.8=56.84N

So kinetic frictional force will be equal to 56.84 N

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Which statement best describes a wave?
dedylja [7]

Correct answer choice is:

D. A continuous transmission of energy from one location to the next.

Explanation:

Waves include the carrier of energy without the carrier of matter. In outcome, a wave can be characterized as a change that progresses into a medium, carrying energy from one spot (its source) to different spot without carrying matter.

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3 years ago
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A team of engineering students is testing their newly designed 200 kg raft in the pool where the diving team practices. The raft
elena-s [515]

Answer:

The water level rises more when the cube is located above the raft before submerging.

Explanation:

These kinds of problems are based on the principle of Archimedes, who says that by immersing a body in a volume of water, the initial water level will be increased, raising the water level. That is, the height in the container with water will rise in level. The difference between the new volume and the initial volume of the water will be the volume of the submerged body.

Now we have two moments when the steel cube is held by the raft and when it is at the bottom of the pool.

When the cube is at the bottom of the water we know that the volume will increase, and we can calculate this volume using the volume of the cube.

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Now when a body floats it is because a balance is established in the densities, the density of the body and the density of the water.

Ro_{H2O}=R_{c+r}\\where:\\Ro_{H2O}= water density = 1000 [kg/m^3]\\Ro_{c+r}= combined density cube + raft [kg/m^3]

Density is given by:

Ro = m/V

where:

m= mass [kg]

V = volume [m^3]

The buoyancy force can be calculated using the following equation:

F_{B}=W=Ro_{H20}*g*Vs\\W = (200+730)*9.81\\W=9123.3[N]\\\\9123=1000*9.81*Vs\\Vs = 0.93 [m^3]

Vs > Vc, What it means is that the combined volume of the raft and the cube is greater than that of the cube at the bottom of the pool. Therefore the water level rises more when the cube is located above the raft before submerging.

7 0
4 years ago
A force of 80 N is exerted on an object on a frictionless surface for a distance of 4 meters. If the object has a mass of 10 kg,
solmaris [256]
There are two ways to find energy. Energy=F*d=mv^2. We can use this relationship to find v:
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3 years ago
Planets that are cold have only a small amount of gravity
Nonamiya [84]
There is no theoretical OR observational evidence for that statement.
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4 years ago
Driving along a boring stretch of interstate in Illinois, you start experimenting using the average speed equation you learned i
astra-53 [7]
The average speed would be 33.29m/s.
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Average speed =  \frac{total distance}{total time}

First you will need to solve for the distance you traveled in each scenario. So we can solve this by getting the product of speed and the time traveled. 

Scenario 1:
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Time = 120s
Distance = ?

Distance = (29m/s)(120s)
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Scenario 2
Speed = 35m/s
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Distance = (35m/s)(300s)
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Average speed = \frac{total distance}{total time}
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                                = 33.29m/s
5 0
3 years ago
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