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iren [92.7K]
3 years ago
10

What property of a solid would be most important if you were calculating how much paint was required to cover it?

Physics
1 answer:
Nadusha1986 [10]3 years ago
6 0
Define shape and volume

Because: The area of the shape is how much paint would cover the object
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A stone is launched at an angle of 50 degree with initial velocity of 22m/s. Find out its initial and final velocity.​
ss7ja [257]

(a) The initial vertical velocity of the stone is 16.85 m/s and the initial horizontal velocity is 14.14 m/s.

(b) The final vertical velocity is 0 and the final horizontal velocity is 14.14 m/s.

<h3>Initial vertical velocity</h3>

The initial vertical velocity of the stone is calculated as follows;

Vi = Vsinθ

Vi = 22 x sin(50)

Vi = 16.85 m/s

<h3>Initial horizontal velocity</h3>

Vxi = V cosθ

Vxi = 22 x cos(50)

Vxi = 14.14 m/s

<h3>Final vertical velocity of the stone</h3>

Vf = Vi - gt

where;

  • Vf is the final vertical velocity = 0 at maximum height
<h3 /><h3>Final horizontal velocity of the stone</h3>

Vfx = Vxi = 14.14 m/s

Thus, the initial vertical velocity of the stone is 16.85 m/s and the initial horizontal velocity is 14.14 m/s.

The final vertical velocity is 0 and the final horizontal velocity is 14.14 m/s.

Learn more about vertical velocity here: brainly.com/question/24949996

#SPJ1

3 0
2 years ago
At the equator, the radius of the Earth is approximately 6370 km. A plane flies at a very low altitude at a constant speed of v
Cerrena [4.2K]

To solve this problem we will apply the concepts related to the kinematic equations of linear motion. From there we will define the distance as the circumference of the earth (approximate as a sphere). With the speed given in the statement we will simply clear the equations below and find the time.

R= 6370*10^3 m

v = 239m/s

a = 16.5m/s^2

The circumference of the earth would be

\phi = 2\pi R

Velocity is defined as,

v = \frac{x}{t}

t = \frac{x}{v}

Here x = \phi, then

t = \frac{\phi}{v} = \frac{2\pi (6370*10^3)}{239}

t = 167463.97s

Therefore will take 167463.97 s or 1 day 22 hours 31 minutes and 3.97seconds

4 0
3 years ago
The combination of all of the forces acting on an object is called the
Veronika [31]
The answer is Net force
6 0
3 years ago
In a fluorescent tube of diameter 3 cm, 3 1018 electrons and 0.75 1018 positive ions (with a charge of e) flow through a cross-s
Vinil7 [7]

Answer:

The  current in the tube is 0.601 A

Explanation:

Given;

diameter of the fluorescent, d = 3 cm

negative charge flowing in the fluorescent tube, -e = 3 x 10¹⁸ electrons/second

positive charge flowing in the fluorescent tube, +e = 0.75 x 10¹⁸ electrons/ second

The current in the fluorescent tube is due to presence of positive and negative charges to create neutrality in the conductor (fluorescent tube).

Q = It

I = Q/t

where;

I is current in Ampere (A)

Q is charge in Coulombs (C)

t is time is seconds (s)

1 e = 1.602 x 10⁻¹⁹ C

3 x 10¹⁸ e/ s = ?

= (3 x 10¹⁸ e/s  x 1.602 x 10⁻¹⁹ C) / 1e

= 0.4806 C/s

negative charge per second (Q/t) = 0.4806 C/s

positive charge per second (Q/t) =  (0.75 x 10¹⁸ e/s  x 1.602 x 10⁻¹⁹ C) / 1e

positive charge per second (Q/t) = 0.12015 C/s

Total charge per second in the tube, Q / t = (0.4806 C/s + 0.12015 C/s)

                                                                I = 0.601 A

Therefore, the  current in the tube is 0.601 A

7 0
3 years ago
the electric field midway between two equal but opposite point charges is 573 n/c , and the distance between the charges is 16.0
saveliy_v [14]

The electric potential  between the two charges is 91.68 V.

<h3>Electric potential between the two charges</h3>

The electric potential  between the two charges is calculated as follows;

V = Ed

where;

  • V is electric potential
  • E is electric field
  • d is the distance of the charge

Substitute the given parameters and solve for electric potential,

V = 573 N/c x 0.16 m

V = 91.68 V

Thus, the electric potential  between the two charges is 91.68 V.

Learn more about electric potential here: brainly.com/question/26978411

#SPJ4

4 0
1 year ago
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