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docker41 [41]
3 years ago
10

Explain how the pressure at the bottom of a container depends on the container shape and the fluid height

Physics
1 answer:
3241004551 [841]3 years ago
3 0

The pressure at the bottom of a column of fluid in a container
depends only on the depth of the fluid, not on the shape of the
container.  The pressure is simply the result of the weight of the
fluid resting on the bottom.

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If a positive test charge is placed in an electric field, what is the direction of the force on the test charge?
svetlana [45]

Explanation:

If a positive test charge is placed in an electric field, it will exert the force in the test charge in the direction of electric field vector. We know that the direction of electric field is given by electric field lines. The field lines for a positive charge is outwards. The electric force acting on the charge is given by :

F = q E

Hence, this is the required solution.

6 0
3 years ago
The special theory of relativity deals with space and time under what special condition?
sergij07 [2.7K]
<h2>Answer: Invariance of the speed of light in vacuum  </h2>

Special relativity was proposed on 1905 by Einstein, who developed his theory based on the following two postulates:  

<em>1. The laws of physics are the same in all inertial systems. There is no preferential system.  </em>

<em>2. The speed of light in vacuum has the same value for all inertial systems.  </em>

<em></em>

Focusing on the first postulate, it can be affirmed that any measurement on a body is made with reference to the system in which it is being measured.

 

In addition, it deals with the <u>dilation of time</u> stating that <u>time passes at different rates in regions of different gravitational potential</u>. That is, the greater the local distortion of space-time due to gravity, the slower the time passes.  

On the other hand, following what relativity establishes, bodies within a gravitational field follow a curved space path.  

7 0
3 years ago
Why are movie scenes in outer space often unrealistic?
kifflom [539]

Answer:

see explanation

Explanation:

by my calculations, i believe it may be because they have to pretend to be in space.

8 0
2 years ago
Read 2 more answers
An object is placed 50cm in front of a concave mirror of radius 60cm. How far from the mirror is the image?
Shkiper50 [21]

Answer:To explian the exact calculation of this pruduct we must not try!

3 0
3 years ago
A long solenoid, of radius a, is driven by an alternating current, so that the field inside is sinusoidal: B(t) B cos(ot)ż. A ci
Scrat [10]

Answer:

The current induced in the loop is \dfrac{\pi a^2 B\omega}{4R}\ \sin(\omega t).

Explanation:

Given that,

Magnetic field B(t)=B\cos(\omega t)\ z

Radius r =\dfrac{a}{2}

Resistance =R

We need to calculate the area of the loop

Using formula of area

A = \pi r^2

Put the value of r in to the formula

A =\pi\times(\dfrac{a}{2})^2

A=\dfrac{\pi a^2}{4}

We need to calculate the flux

Using formula of flux

\phi=BA

\phi=B\cos(\omega t)\dfrac{\pi a^2}{2}

We need to calculate the emf

Using formula of emf

\epsilon=-\dfrac{d\phi}{dt}

\epsilon=-\dfrac{-\pi a^2B}{4}(-\omega\sin\omega t)

\epsilon=\dfrac{\pi a^2B\omega\sin(\omega t)}{4}

We need to calculate the current

Using formula of current

I(t)=\dfrac{\epsilon}{R}

I(t)=\dfrac{\dfrac{\pi a^2B\omega\sin(\omega t)}{4}}{R}

I(t)=\dfrac{\pi a^2 B\omega}{4R}\ \sin(\omega t)

Hence, The current induced in the loop is \dfrac{\pi a^2 B\omega}{4R}\ \sin(\omega t).

4 0
3 years ago
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