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rosijanka [135]

3 years ago

15

A stone falls freely from rest for 8.0s what is it final velocity

1 answer:

NemiM [27]3 years ago

7 0

Is that the full question?

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Which of these statements best describes the role of creativity in science?

It helps scientists create theories which are universal.

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Why is it important for scientists to measure how much precipitation is falling across the world?

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The grant that considered the foundation of financial aid is the:

navik [9.2K]

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A cannon of mass 5.71 x 103 kg is rigidly bolted to the earth so it can recoil only by a negligible amount. The cannon fires a 7

zheka24 [161]

Answer:

541.14 m/s

Explanation:

We are given that

Mass of cannon= $m_1=5.71\times 10^3 kg$

Mass of shell, $m_2=73.5 kg$

Initial velocity of shell,v=547 m/s

We have to find the velocity of shell fired from this loose cannon.

According to law of conservation of momentum

$m_1v_1+m_2v_2=m_1u_1+m_2u_2$

Initial momentum of system=0

$m_1v_1=-m_2v_2$

$v_1=-\frac{m_2v_2}{m_1}$

When the cannon is bolted to the ground then only shell moves and kinetic energy of system equals to kinetic energy of shell

Kinetic energy of shell, $K.E=\frac{1}{2}mv^2=\frac{1}{2}\times 73.5(547)^2}=1.09\times 10^7 J$

K.E of shell= $\frac{1}{2}m_1v^2_1+\frac{1}{2}m_2v^2_2$

K.E of shell= $\frac{1}{2}m_1(-\frac{m_2v_2}{m_1})^2+\frac{1}{2}m_2v^2_2$

K.E of shell= $\frac{1}{2}(\frac{m^2_2v^2_2}{m_1}+\frac{1}{2}m_2v^2_2)$

2K.E of shell= $m_2v^2_2(\frac{m_2}{m_1}+1)$

Velocity of shell fired from this loose cannon,v_2= $\sqrt{\frac{2k.E}{m_2(\frac{m_2}{m_1}+1)}$

$v_2=\sqrt{\frac{2\times 1.09\times 10^7}{73.5(\frac{73.5}{5.71\times 10^3}+1)}$

$v_2=541.14m/s$

Hence, the velocity of shell fired from this loose cannon would be 541.14 m/s

5 0

3 years ago

Please show work and tell me how you did it.

Ilya [14]

Explanation:

1) speed of bicycle = $\frac{distance}{time}$

speed of bicycle= $\frac{20}{2}$

speed of bicycle = 10 miles/hour

2)speed of rocket = $\frac{distance}{time}$

speed of rocket= $\frac{9000}{12.12}$

speed of rocket= 742.57 meter/second

3)speed of jet plane = $\frac{distance}{time}$

speed of jet plane= $\frac{528}{4}$

speed of jet plane= 132 meter/second

4)speed = $\frac{distance}{time}$

time = $\frac{distance}{speed}$

time of trip= $\frac{350}{80}$

time of trip = 4.375 hour

5) Distance = speed × time

Distance = 6 × 3 × 60

Distance = 1080 meter

6) Average speed = $\frac{total distance}{total time}$

Average speed = $\frac{816}{10}$

Average speed = 81.6 km/hour

7) Time = $\frac{Distance}{speed}$

Time = $\frac{450 \times 1000}{120}$

Time = 3750 m/s

4 0

3 years ago