Answer:
See the explanation below.
Explanation:
Resistance C is connected in parallel with the 120 V voltage source, so we can determine the current through this resistance by the ohm law.
I = V / R
where:
V = voltage [volt]
R = resistance [ohm]
I = 120 / 100
I = 1.2[amp]
The resistors d, e & f, are connected in series, therefore you can calculate the total resistance of them by performing an algebraic sum.
Rt = 400 + 200 + 200 = 800 [ohm]
This total resistance, will be connected in parallel, with the voltage source in this way we can calculate the current that passes through it through the ohm law.
I2 = 120 / 800 = 0.15 [amp]
The resistors a & b, are connected in series, therefore you can calculate the total resistance of them by performing an algebraic sum.
Rt2 = 100 + 100 = 200 [ohm]
This total resistance, will be connected in parallel, with the voltage source in this way we can calculate the current that passes through it through the ohm law.
I3 = 120 / 200 = 0.6 [amp]
Now we can write the currents for each of the resistors.
a ) I = 0.6 [amp]
b) I = 0.6 [amp]
c) I = 1.2 [amp]
d) I = 0.15 [amp]
e) I = 0.15 [amp]
f) I = 0.15 [amp]
