The cliff is 2042 ft away.
We know that the speed of sound in air is directly proportional to the absolute temperature.
First convert the Fahrenheit temperature to Celsius;
°C = 5/9(44.5 - 32)
°C = 6.9 °C
Applying the formula;
V1/V2 = √T1/T2
Where; V1 = velocity of sound in air at 0°C
V2 = Velocity of sound in air at 6.9 °C
1087/V2 = √273/279.9
V2= 1101 ft/s
Given that; V = 2s/t
Where s is the distance of the cliff
t is the time taken
1101 ft/s = 2s/3.71 s
s = 1101 ft/s × 3.71 s/2
s = 2042 ft
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The answer would be A which is waves.
Answer:
I = 274.75 kg-m²
Explanation:
given,
mass of horizontal platform = 129 Kg
radius of the disk = 1.51 m
mass of the person(m_p) = 67.5 Kg
standing at distance(r_p) = 1.09 m
mass of dog(m_d) = 25.3 Kg
sitting near the person(r_d) = 1.37 m from center
moment of inertia = ?
Moment of inertia of disc = 
Moment of inertia of the system



I = 274.75 kg-m²