The dependent variable is: <em>"number of vocabulary words subjects can remember"</em>
<h3>
Which is the dependent variable?</h3>
In an experiment, we basically see how changing one variable affects another variable.
In this case, the experiment is:
<em>" if sleep affects the number of vocabulary words subjects can remember."</em>
Then the hours of sleep would be the independent variable (the one that the scientist can change) and the number of vocabulary words subjects can remember is the dependent variable (that depends on the independent variable).
So the correct answer is:
<em>"number of vocabulary words subjects can remember"</em>
If you want to learn more about variables:
brainly.com/question/15246027
#SPJ1
Answer:She would need to first know the weight of the sculpture and what she is going to move it with then she will need to use newton's second law to calculate the amount of force needed to move it
Explanation: I just did the assignment on edgunity
The appropriate PPE(personal protective equipment) to be worn for foot protection against electric shock is boots retrofitted with rubber soles. Rubber does not conduct electricity and so will safeguard against electric shocks.
Other personal protective equipment used in a lab or industry can include safety glasses, rubber gloves, protective clothing and masks and respirators. PPE goes hand in hand with personal behaviour, personal grooming and housekeeping.
Answer: 2.3m/s
Explanation:
mass-energy balance: ke(f) + pe(f) = ke(o) + pe(o)
since we are looking for the point at the bottom of the pendulum, thats the reference point, the lowest in the system. pe(f) is 0, since h
ke(f)=0.5m x v(f)^2
pe(f)=0
ke(o)=0.5m x v(o)^2
pe(o)-mxgxh
find h by: drawing a triangle with the pendulum at the vertical, then displaced by 25 degrees , The difference in height is h, because cos(25)=(adj)/(hyp)=(2-h)/2. I found h=0.187m
In the m-e balance, cancel the masses in all the terms.
.5xv(f)^2 =0.5v(o)^2 +gxh
Given v(o) = 1.2 m/s and g = 9.8 then v(f) = 2.2595 m/s
Therefore V(0) = 2.3 m/s
Power = (1000 kilo-Watt-hr/mo) x (1000/kilo) x (mo/30day) x (day/24 hr)
Power = (1000 x 1000 / 30 x 24) (kilo-watt-hr-mo-day/mo-kilo-day-hr)
Power = (1,000,000/720) watt
(voltage x current) = (1,000,000/720) watts
120v x current = (1,000,000/720) watts
Current = 1,000,000 / (720 x 120) Amperes
<em>Current = 11.57 Amperes</em>