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Bumek [7]
3 years ago
12

Two speakers both emit sound of frequency 320 Hz, and are in phase. A receiver sits 2.3 m from one speaker, and 2.9 m from the o

ther. What is the phase difference between the two sounds detected by the receiver?
a. 32.3 λλ
b. 0.60 λλ
c. 0.089 λλ
d. 0.29 λλ
e. 0.56 λλ
Physics
1 answer:
satela [25.4K]3 years ago
3 0

Answer:

Option B

Explanation:

The phase difference is found by subtracting the 2.3m for the receiver from the other speaker which is 2.9m hence

Phase difference= 2.9-2.3= 0.6

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<h2>Answer:</h2>

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The sound intensity level (β), measured in decibels, of a sound with an intensity of I is defined as follows;

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Substitute this value into equation (i) as follows;

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Solve for I;

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