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Bumek [7]
3 years ago
12

Two speakers both emit sound of frequency 320 Hz, and are in phase. A receiver sits 2.3 m from one speaker, and 2.9 m from the o

ther. What is the phase difference between the two sounds detected by the receiver?
a. 32.3 λλ
b. 0.60 λλ
c. 0.089 λλ
d. 0.29 λλ
e. 0.56 λλ
Physics
1 answer:
satela [25.4K]3 years ago
3 0

Answer:

Option B

Explanation:

The phase difference is found by subtracting the 2.3m for the receiver from the other speaker which is 2.9m hence

Phase difference= 2.9-2.3= 0.6

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A passenger in a helicopter traveling upwards at 15 m/s accidentally drops a package out the window. If it takes 15 seconds to r
Alexeev081 [22]

Answer:

The helicopter was 1103.63 meters high when the package was dropped.

Explanation:

We consider positive speed as a downward movement

y: height (m)

t: time (s)

v₀: initial speed (m/s)

Δy = v₀t + \frac{1}{2}gt²

Δy= 15\frac{m}{s}×15 s + \frac{1}{2}×9.81\frac{m}{s^{2} }×(15 s)²

Δy= 1103.63 m

8 0
3 years ago
A flexible shaft consists of a 3 mm diameter steel wire in a flexible hollow tube which imposes a frictional torque of 0.04 N m
Rom4ik [11]

Answer:

2.5m

Explanation:

Torque is defined as the rotational effect of a force on a body.

The torque T for the maximum shear stress is given as 0.1 Nm

Frictional torque is the torque caused by a frictional force

The frictional torque F is given as 0.04 Nm/m

The maximum length of the shaft is thus given as

L = T / F

  = 0.1/0.04

L= 2.5 m

6 0
4 years ago
If a blue whale weighs 200 tons what would it be on the moon?
sasho [114]

Answer:

if no mistaken then it is 300kN

Explanation:

Using SI units (the default if a system is not specified) 200T = 200000kg as the mass of the whale, it would weigh 1960kN in 1g Earth gravity.

On the Moon, the acceleration is 0.166g, to it would weigh about 330kN.

7 0
3 years ago
Read 2 more answers
A runner taking part in the 200 m dash must run around the end of a track that has a circular arc with a radius of curvature of
nlexa [21]

Answer:

a_c=1.44\ m/s^2

Explanation:

<u>Centripetal Acceleration</u>

It's the acceleration that an object has when traveling on a circular path to take into consideration the constant change of velocity it must have in order to keep going in the circular path.

Being v the tangent speed, and r the radius of curvature of the circle, then the centripetal acceleration is given by

\displaystyle a_c=\frac{v^2}{r}

We can compute the value of v by using the distance and the time taken to travel:

\displaystyle v=\frac{x}{t}=\frac{200\ m}{26.4\ s}

v=7.58\ m/s

Now we calculate the centripetal acceleration

\displaystyle a_c=\frac{7.58^2}{40}=1.44\ m/s^2

\boxed{a_c=1.44\ m/s^2}

4 0
3 years ago
A vector has a magnitude of 82 m
pentagon [3]

The Y-component of the vector is 34.65 m.

<h3>What is a vector?</h3>

Vectors are quantities that have both magnitude and direction.

The Y-component of the vector can be calculated using the formula below.

Formula:

  • Y = rsin∅............. Equation 1

Where:

  • Y = Y-component of the vector
  • r = magnitude of the vector
  • ∅ = angle of the vector to the horizontal.

From the question,

Given:

  • r = 82 m
  • ∅ = 25°

Substitute these given values into equation 1

  • Y = 82(sin25°)
  • Y = 34.65 m

Hence, The Y-component of the vector is 34.65 m.
Learn more about vectors here: brainly.com/question/24855749

7 0
2 years ago
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