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Sati [7]
3 years ago
8

Calculate the following

Physics
1 answer:
aniked [119]3 years ago
6 0
Garth morning was the night of the day you guys got the nitro back
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PLEASE HELP!!! I'm dumb lol.
Len [333]

Answer:

A theory or hypothesis does not necessarily provide an accurate scientific explanation to any topic but predicts what can happen.

Explanation:

7 0
2 years ago
Read 2 more answers
1. If a car travels 400m in 20 seconds how fast is it going?
Marrrta [24]

Answer:

1) 20 m/s

2) 5 m/s

3) 2 m/s

4) 395,000m/9000s

5) 16 km/0.25h

Explanation:

i dunno

5 0
3 years ago
What makes a model not useful?
lina2011 [118]
Answer is b hope this helps
8 0
3 years ago
Assuming all object are moving with the same velocity, witch statement describes the object with the largest intertia?
Kisachek [45]

Answer:

Mass is the quantitative measure of inertia of any object.

Explanation:

The object that have largest mass will   have largest inertia as well as largest momentum.

3 0
3 years ago
In a series lrc circuit, the frequency at which the circuit is at resonance is f0. If you double the resistance, the inductance,
taurus [48]

When you double capacitance and inductance, the new resonance frequency becomes f/2.

  • Resonance frequency:

The resonance frequency of RLC series circuit, is the frequency at which the capacity reactance is equal to inductive reactance.

It can also be defined as the natural frequency of an object where it tends to vibrate at a higher amplitude.

Xc = Xl

which gives the value for resonance frequency:

f = \frac{1}{2\pi \sqrt{LC} }

where;

f is the resonance frequency

L is the inductance

C is the capacitance

When you double capacitance and inductance, the new resonance frequency becomes;

f' = \frac{1}{2\pi \sqrt{2L2C} }

f' = \frac{1}{2\pi \sqrt{4LC} }

f' = \frac{1}{\pi \sqrt{LC} }\frac{1}{2}

f' = \frac{1}{2} f

Thus from above,

When you double capacitance and inductance, the new resonance frequency becomes f/2.

Learn more about resonance frequency here:

<u>brainly.com/question/13040523</u>

#SPJ4

6 0
2 years ago
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