Ethyl alcohol, CH3CH2OH2, is misconception with octane, C8H18, but plenty alcohol, CH3CH2CH2CH2CH3OH3, is soluble in water only
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Answer:
11.6 mL of 0.1400 M of NaOH is required to reach equivalence point.
Explanation:
Chloroacetic acid is an monoprotic acid.
Neutralization reaction:
So, 1 mol of chloroacetic acid is neutralized by 1 mol of NaOH.
Molar mass of chloroacetic acid = 94.5 g/mol
So, 0.154 g of chloroacetic acid = moles of chloroacetic acid
= 0.00163 moles of chloroacetic acid
Lets assume V mL of 0.1400 M of NaOH is required to reach equivalence point.
So, number of moles of NaOH needed to reach equivalence point
= moles
So,
or, V = 11.6
Hence, 11.6 mL of 0.1400 M of NaOH is required to reach equivalence point.