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3 years ago

The diagram below shows eight different positions of the moon around Earth.

Physics

1 answer:

KATRIN_1 [288]3 years ago

6 0

Answer:

6 and 8

Explanation:

The different positions of the moon, as seen from Earth, reflect how much light is being reflected off the moon from the sun.

Position 1 indicates the 3rd Quarter.

Position 2 indicates the Waning Gibbous.

Position 3 indicates the Full Moon.

Position 4 indicates the Waxing Gibbous.

Position 5 indicates the 1st Quarter.

Position 6 indicates the Waxing Crescent.

Position 7 indicates the New Moon.

Position 8 indicates the Waning Crescent.

You would read the diagram counterclockwise, with positions 7 to 3 as the moon increases light and positions 3 to 7 as the moon decreases light.

Therefore, we see that our 2 choices where we have a crescent is positions 6 and 8.

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Calculate the accleration of a car if its velocity increases from 15m/s to 75m/s in 5 second

andrezito [222]

Answer:

I think the acceleration is 12m/s

3 0

2 years ago

If 5 mm of rain falls in a 100 m2 field, what volume of rain, in m3, fell in the field?

Nina [5.8K]

The volume of rain that fells in the field is simply given by the area of the field, which is

$A=100 mm^2$

multiplied by the height of rain that fell, which is

$h=5.0 mm$

Therefore, the volume is

$V=hA=(5 mm)(100 mm^2)=500 mm^3$

7 0

3 years ago

If you throw a ball down ward then acceleration immeditely after leaving your hand is

bezimeni [28]

Answer:

9.8m/s²

Explanation:

The acceleration of the ball thrown after leaving my hand is 9.8m/s². This will be the acceleration due to gravity on the body.

Acceleration due to gravity is caused by the pull of the earth on a massive object.
The value of this acceleration is 9.8m/s².
As the ball nears the surface, it comes near zero.

7 0

2 years ago

. A ball is thrown downward at a speed of 20 m/s. Choosing

a_sh-v [17]

The final velocity is $v = 20 - gt$

The distance traveled by the ball at time t is $y = y_o + (-20)t - \frac{1}{2} gt^2$

The maximum distance traveled by the object is $0 = (20)^2 - 2g(y-y_0)$

The given parameters;

initial velocity of the ball, u = 20 m/s

acceleration due to gravity, g = 9.8 m/s²

The final velocity can be calculate as;

$v = 20 - gt$

The distance traveled by the ball at time t;

$y = y_o + (-20)t - \frac{1}{2} gt^2$

The maximum distance traveled by the object is calculated as;

$v^2 = u^2 - 2g(y - y_0)\\\\0 = (20)^2 - 2g(y-y_0)$

Learn more here: brainly.com/question/16878713

3 0

2 years ago

ANSWER FAST PLEASE HELP

KengaRu [80]

Answer:

B. 175 N

Explanation:

Net force can be defined as the vector sum of all the forces acting on a body or an object i.e the sum of all forces acting simultaneously on a body or an object.

Mathematically, net force is given by the formula;

$Fnet = Fapp + Fg$

Where;

Fnet is the net force

Fapp is the applied force

Fg is the force due to gravitation

In this scenario, we observed that both forces are acting in the same direction.

Therefore:

Net force = 100 N + 75 N

Net force = 175 Newton

6 0

2 years ago