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denpristay [2]
3 years ago
15

It is desiredto FDM 30voice channels (each with a bandwidth of 4.5KHz) along with a guard band of 0.8KHz. Ignoring a guard band

before the first channel and the one after the last channel, what is the total bandwidth, in KHz,required for such a system.
Physics
1 answer:
Hitman42 [59]3 years ago
4 0

Answer:

Total bandwidth required  = 158.2 KHz

Explanation:

given data:

number of channel 30

bandwidth of each channel is 4.5 KHz

bandwidth of guard band 0.8 KHz

According to the given information, first guard band and the guard band after last channel should be ignored, therefore we have total number of  29 guard band.

As per data, we can calculate total bandwidth  required

total bandwidth = 30*4.5 + 29*0.8

total bandwidth required  = 158.2 KHz

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Young's experiment is performed with light of wavelength 502 nm from excited helium atoms. Fringes are measured carefully on a s
PSYCHO15rus [73]

Answer:

Explanation:

wave length of light λ = 502 nm

screen distance D = 1.2 m

width of one fringe = 10.2 mm / 20

= .51 mm

fringe width = λ D / a  , a is separation of slits

Puting the values given

.51 x 10⁻³ =  502 x 10⁻⁹ x 1.2 / a

a = 502 x 10⁻⁹ x 1.2 / .51 x 10⁻³

= 1181.17 x 10⁻⁶ m

1.18 x 10⁻³ m

= 1.18 mm .

8 0
3 years ago
. A laser beam shines along the surface of a block of transparent material (see Fig. E33.8). Half of the beam goes straight to a
Neporo4naja [7]

Answer:

n = 1,875

Explanation:

The speed of light in vacuum is constant (c) and in a material medium it is

          v = d / t

The refractive index of a material is defined by

         n = c / v

         

Let's look for the speed of light in the material, in general the length that light travels is known, this value is high, x = 1, when we place a block on the road, a small amount is lengthened by the length of the block, which in general is despised

These measurements are made on a digital oscilloscope that allows to stop the signals and measure their differences, that is, the zero is taken when the first ray arrives and the time for the second ray is measured,

         

         v = d / t

         v = 1 / 6.25 10⁻⁹

         v = 1.6 10⁸ m / s

we calculate the refractive index

        n = 3 10⁸ / 1.6 10⁸

        n = 1,875

6 0
3 years ago
Match the organs to the functions they perform during digestion.<br> passes food to esophagus
mixas84 [53]

Answer:

the mouth I think

Because: the oesophagus is the throat and the mouth is how the food gets to the oesophagus. might be wrong because I'm not sure about the organ part but I'm pretty sure that's all it could be

8 0
4 years ago
A small but measurable current of 3.8 × 10-10 A exists in a copper wire whose diameter is 2.5 mm. The number of charge carriers
Karolina [17]

Answer:

a) 4.9*10^-6

b) 5.71*10^-15

Explanation:

Given

current, I = 3.8*10^-10A

Diameter, D = 2.5mm

n = 8.49*10^28

The equation for current density and speed drift is

J = I/A = (ne) Vd

A = πD²/4

A = π*0.0025²/4

A = π*6.25*10^-6/4

A = 4.9*10^-6

Now,

J = I/A

J = 3.8*10^-10/4.9*10^-6

J = 7.76*10^-5

Electron drift speed is

J = (ne) Vd

Vd = J/(ne)

Vd = 7.76*10^-5/(8.49*10^28)*(1.60*10^-19)

Vd = 7.76*10^-5/1.3584*10^10

Vd = 5.71*10^-15

Therefore, the current density and speed drift are 4.9*10^-6

And 5.71*10^-15 respectively

3 0
3 years ago
What is an example of convection currents? a. marshmallows toasting over a campfire b. a pot being heated by an electric burner,
SCORPION-xisa [38]

Answer:

B

Explanation:

because, convection is the transfer of heat between fluid substances/materials

7 0
3 years ago
Read 2 more answers
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