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ziro4ka [17]
3 years ago
9

how many championships did Kobe Bryant have? when did he retire? when did kobe be called the black mamba?

Physics
2 answers:
ser-zykov [4K]3 years ago
8 0

Answer:

kobe has passed away

Explanation:

vichka [17]3 years ago
3 0

Answer:

1: 5

2: April 13, 2016

3: it was for an alter ego he made the name to deal with the issues regarding the court

hope i helped good luckkk

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What is the velocity of an object that has been in free fall for 2.5
Vladimir79 [104]

Answer: calculate the free fall distance and velocity without air resistance from, the free fall.

Explanation:

To find out something's speed (or velocity) after a certain amount of time, you just multiply the acceleration of gravity by the amount of time since it was let go of. So you get: velocity = -9.81 m/s^2 * time, or V = gt. The negative sign just means that the object is moving downwards

8 0
3 years ago
An Indy 500 race car's velocity increases from 4.0 m/s to +36
Soloha48 [4]

Answer:

The average acceleration is 8\ m/s^2

Explanation:

<u>Uniform Acceleration </u>

When an object varies its velocity at the same rate, the acceleration is constant.

The relation between the initial and final speeds is:

v_f=v_o+a.t

Where:

vf  = Final speed

vo = Initial speed

a   = Constant acceleration

t   = Elapsed time

The acceleration can be calculated by solving for a:

\displaystyle a=\frac{v_f-v_o}{t}

The Indy 500 race car increases its speed from vo=4 m/s to vf=36 m/s in t=4 s. Thus, the average acceleration is:

\displaystyle a=\frac{36-4}{4}=8\ m/s^2

The average acceleration is 8\ m/s^2

3 0
3 years ago
A 12cm candle is placed 6cm from a converging lens with a focal length of 15cm. What is the height of the image of the candle? S
amm1812

Answer:

The height of the image of the candle is 20 cm.

Explanation:

Given that,

Size of the candle, h = 12 cm

Object distance from the candle, u = -6 cm

Focal length of converging lens, f = 15 cm

To find,

The height of the image of the candle.

Solution,

Firstly, we will find the image distance of the candle. Let it is equal to v. Using lens formula to find the image distance.

\dfrac{1}{f}=\dfrac{1}{v}-\dfrac{1}{u}

v is image distance

\dfrac{1}{f}=\dfrac{1}{v}-\dfrac{1}{u}\\\\\dfrac{1}{v}=\dfrac{1}{f}+\dfrac{1}{u}\\\\\dfrac{1}{v}=\dfrac{1}{15}+\dfrac{1}{(-6)}\\\\v=-10\ cm

If h' is the height of the image. Magnification is given by :

m=\dfrac{h'}{h}=\dfrac{v}{u}

h'=\dfrac{vh}{u}\\\\h'=\dfrac{-10\times 12}{-6}\\\\h'=20\ cm

So, the height of the image of the candle is 20 cm.

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3 years ago
What factors do NOT affect friction between two objects? Explain how you know this.
Black_prince [1.1K]

The frictional force between two bodies depends mainly on three factors: (I) the adhesion between body surfaces

(ii) roughness of the surface

(iii) deformation of bodies.

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