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4 years ago

Sound waves tend to move in?

Physics

1 answer:

3241004551 [841]4 years ago

5 0

A sound wave is a means of transporting energy without transporting matter.

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Human perception of the frequency of sound waves is called:

Olin [163]

Answer:

The study of the human perception of sound is called psychoacoustics.

Explanation:

5 0

3 years ago

A hoodlum throws a stone vertically downward with an initial speed v0 from the roof of a building, a height h above the ground.

Vaselesa [24]

V2=u2+2as
v2=144+600
v2=744
v=√744

6 0

4 years ago

A 2.50 gram rectangular object has measurements of 22.0 mm, 13.5 mm, and 12.5 mm. what is the objectâs density in units of g/ml?

navik [9.2K]

To calculate the density, we must first calculate the volume of the object. For a rectangle, the volume is equal to V=l*w*h. In this case, V=22*13.5*12.5=3712.5 mm^3. Next we have to convert the mm^3 to mL using the conversion factor of 1 mm^3=.001 mL. To get mL, we set up the expression 3712.5 mm^3 * (.001mL/1mm^3) = 3.7125 mL. Finally, to get the density, we know density is mass over volume, so we set the expression p=m/V=2.5g/3.7125mL=.6734 which rounded to 3 significant figures is .673. The answer will be .673

8 0

3 years ago

1.00kg of ice at -24 degrees Celsius is placed in contact with a 1.00kg block of a metal at 5.00 degrees Celsius. They come to e

Alona [7]

Answer:

C₂ = 2.22 KJ/kg °C

Explanation:

Since, both objects are in thermal contact. Therefore, the law of conservation of energy tells us that:

$Heat\ Lost\ by\ Metal\ Block = Heat\ Gained\ by\ Ice\\m_{1}C_{1} \Delta T_{1} = m_{2}C_{2} \Delta T_{2}$

where,

m₁ = mass of ice = 1 kg

C₁ = specific heat of ice = 2.04 KJ/kg.°C

ΔT₁ = Change in Temperature of Ice = -8.88°C - (-24°C) = 15.12°C

m₂ = mass of metal block = 1 kg

C₂ = specific heat of metal = ?

ΔT₂ = Change in Temperature of Metal Block = 5°C - (-8.88°C) = 13.88°C

Therefore, using these values in the equation, we get:

$(1\ kg)(2.04\ KJ/kg.^0C)(15.12\ ^0C) = (1\ kg)C_{2}(13.88\ ^0C) \\C_{2} = \frac{30.84\ KJ}{13.88\ kg/^0C}$

C₂ = 2.22 KJ/kg °C

4 0

3 years ago

Read 2 more answers

If we use a 10cm converging lens instead of a 5cm converging lens, would the first point at which the image focuses (as you slid

maks197457 [2]

Answer:

first point at which the image focuses will be closer

Explanation:

given data

converging lens = 10 cm

converging lens = 5 cm

lens = 5 cm

to find out

would the first point at which the image focuses be closer or farther

solution

we apply here lens formula that is

1/f = 1/u + 1/v ......................1

so here

v = f × u / u - f

so here for f = 10 cm v will be

v = 10u / u-10 ..........................2

and

for f = 5 cm v will be

v = 5u / u-5 . ........................3

now if we compare equation 2 and 3 we can say that

v for f = 5 cm is greater than v for f = 10 cm

so here first point at which the image focuses will be closer

4 0

3 years ago