Angstrom = 10^-10 m
for nucleus size are used fermi (femtometer 10^-15 m )
The highest point<span> of the </span>pendulums<span> swing is when the potential energy is at its </span>highest<span> and the </span>kinetic energy<span> is at its lowest.</span>
C. amphibian eggs do not contain a protective shell
Answer:

Explanation:
The acceleration of a circular motion is given by

where
is the angular velocity and
is the radius.
Angular velocity is related to the period, T, by

Substitute into the previous formula.


This acceleration does not depend on the linear or angular displacement. Hence, the amount of rotation does not change it.