True because my mom said to me this morning that i have to take my breakfast
Answer:
the glove could be heavy so slowing down his power
Explanation:
JUST GUESSED
Answer:
= 1220 nm
= 1.22 μm
Explanation:
given data:
wavelength ![\lambda = 610 nm = 610\times 10 ^{-9} m](https://tex.z-dn.net/?f=%5Clambda%20%3D%20610%20nm%20%3D%20610%5Ctimes%20%2010%20%5E%7B-9%7D%20m)
distance of screen from slits D = 3 m
1st order bright fringe is 4.84 mm
condition for 1 st bright is
---( 1)
and![tan \theta = \frac{y}{ D}](https://tex.z-dn.net/?f=%20tan%20%5Ctheta%20%3D%20%5Cfrac%7By%7D%7B%20D%7D)
![\theta = tan^{-1}\frac{(y }{D})](https://tex.z-dn.net/?f=%20%5Ctheta%20%3D%20tan%5E%7B-1%7D%5Cfrac%7B%28y%20%7D%7BD%7D%29)
= 0.0924 degrees
plug theta value in equation 1 we get
![d sin ( 0.0924) = 610 \times 10 ^{-9}](https://tex.z-dn.net/?f=%20d%20sin%20%28%200.0924%29%20%3D%20610%20%5Ctimes%2010%20%5E%7B-9%7D)
![d = 3.78\times 10^{-4} m](https://tex.z-dn.net/?f=d%20%3D%203.78%5Ctimes%2010%5E%7B-4%7D%20m)
condition for 1 st dark fringe
![d sin \theta =\frac{λ'}{2}](https://tex.z-dn.net/?f=%3Cstrong%3E%20d%20sin%20%5Ctheta%20%3D%5Cfrac%7B%CE%BB%27%7D%7B2%7D%3C%2Fstrong%3E)
![\lambda '= 2 d sin\theta](https://tex.z-dn.net/?f=%5Clambda%20%27%3D%202%20d%20sin%5Ctheta)
= 2λ since from eq (1)
= 1220 nm
= 1.22 μm
Answer: work done = 64,000J or 64KJ.
Explanation:
Work is said to be done if a force applied makes the object to move through a distance in the direction of the applied force. Work is the product of force and perpendicular distance in the direction of the applied force. It is represented by W, measured in Joules(J) and a scalar quantity.
Thus, work done(J)= force(N) × distance(m)
From the the question,
applied force= 1600N
distance=40m
Therefore, work= 1600 × 40
W= 64,000J
But, 1 kilojoules = 1000J
Therefore, 64,000J = 64,000 ÷ 1000
= 64KJ
Work done is 64KJ