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2 years ago

What beat frequencies are possible with tuning forks of frequencies 255, 258, and 260 hz ?

Physics

1 answer:

zavuch27 [327]2 years ago

7 0

Possible beat frequencies with tuning forks of frequencies 255, 258, and 260 Hz are 2, 3 and 5 Hz respectively.

The beat frequency refers to the rate at which the volume is heard to be oscillating from high to low volume. For example, if two complete cycles of high and low volumes are heard every second, the beat frequency is 2 Hz. The beat frequency is always equal to the difference in frequency of the two notes that interfere to produce the beats. So if two sound waves with frequencies of 256 Hz and 254 Hz are played simultaneously, a beat frequency of 2 Hz will be detected. A common physics demonstration involves producing beats using two tuning forks with very similar frequencies. If a tine on one of two identical tuning forks is wrapped with a rubber band, then that tuning forks frequency will be lowered. If both tuning forks are vibrated together, then they produce sounds with slightly different frequencies. These sounds will interfere to produce detectable beats. The human ear is capable of detecting beats with frequencies of 7 Hz and below.

A piano tuner frequently utilizes the phenomenon of beats to tune a piano string. She will pluck the string and tap a tuning fork at the same time. If the two sound sources - the piano string and the tuning fork - produce detectable beats then their frequencies are not identical. She will then adjust the tension of the piano string and repeat the process until the beats can no longer be heard. As the piano string becomes more in tune with the tuning fork, the beat frequency will be reduced and approach 0 Hz. When beats are no longer heard, the piano string is tuned to the tuning fork; that is, they play the same frequency. The process allows a piano tuner to match the strings' frequency to the frequency of a standardized set of tuning forks.

Learn more about beat frequency here : brainly.com/question/14157895

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Oxygen and life is the only thing earth has

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The surface area of the earth's crust is 5.10*10^8km^2. The average thickness of the earth's crust is 35km. The mean density of

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Answer:

The answer is $V = 1.785 \times 10^{10}\ Km^3$ .

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You are asking only for the total volume, so the important data here is the surface area of the earth's crust,

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and the average thickness of the earth's crust,

$h = 35\ Km$ .

Imagine that you can stretch the surface area as if it were a blanket, now if you want to calculate its volume, you just need to multiply its area by its thickness,

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3 years ago

Color depends on what characteristic of light?

vagabundo [1.1K]

Answer:

a) its frequency

Explanation:

The color of visible light depends only on its frequency, not on the amplitude. In fact, the visible light spectrum can be classified into different colors according to the different frequencies:

Violet: 680-790 THz

Blue: 620-680 THz

Cyan: 600-620 THz

Green: 530-600 THz

Yellow: 510-530 THz

Orange: 480-510 THz

Red: 405-480 THz

And the color of the light has nothing to do with the amplitude of the wave. Therefore, the correct answer is

a) its frequency

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4 years ago

"List, from beginning to end, the stages in the weather as a cold front goes by: (a) warm air is forced upward where it cools; (

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Answer:

(a) warm air is forced upward where it cools;

(c) cumulonimbus or nimbo-stratus clouds form

(d) thunderstorms with heavy showers and gusty winds occur"

(b) air cools and sinks, pressure rises, rain stops;

Explanation:

A cold for front is a denser air , as that forms under the warmer and lighter air mass and this causes a low pressure along the cold form and thus causes the formation of a thunderstorm where enough moisture is present and drop in temperature occurs and in the northern hemisphere the cold front shifts the winds to from the southwest to northwest clockwise.

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3 years ago

Water drips from the nozzle of a shower onto the floor 189 cm below. The drops fall at regular (equal) intervals of time, the fi

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Answer:

0.83999 m

0.20999 m

Explanation:

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s = 189 cm

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When the time intervals are equal, if four drops are falling then we have 3 time intervals.

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For second drop time is given by

$t''=2t'\\\Rightarrow t''=2\times 0.2069133\\\Rightarrow t''=0.4138266\ s$

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Distance from second drop is 0.83999 m

Distance from third drop

$s=ut+\dfrac{1}{2}at^2\\\Rightarrow y''=ut'+\dfrac{1}{2}at'^2\\\Rightarrow s=0\times t+\dfrac{1}{2}\times 9.81\times 0.206913^2\\\Rightarrow s=0.20999\ m$

Distance from third drop is 0.20999 m

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