Which is part of a proper graph?

1 answer:

7 0

The answer is, CC.consistent intervals on each axis. Intervals on each axis should be consistent for easier interpretation of the graph.

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When energy is added to a wave, how can the wave change?.

nadya68 [22]

Answer:

When waves overlap in-phase (crest meets crest or trough meets trough) the waves energy is additive and the amplitude increases.

Explanation:

When waves overlap out-of-phase (crest meets trough) the waves cancel and the amplitude (energy) decreases. When two interfering waves cancel each other out.

6 0

2 years ago

A motorist inflates the tires of her car to a pressure of 180 kPa on a day when the temperature is -8.0° C. When she arrives at

GuDViN [60]

Apply Gay-Lussac's law:

P/T = const.

P = pressure, T = temperature, the quotient of P/T must stay constant.

Initial P and T values:

P = 180kPa, T = -8.0°C = 265.15K

Final P and T values:

P = 245kPa, T = ?

Set the initial and final P/T values equal to each other and solve for the final T:

180/265.15 = 245/T

T = 361K

4 0

3 years ago

A paper airplane is thrown to the north from the top of a cliff with a speed of 2 km/h. The paper airplane lands 15 minutes (0.2

Luden [163]

If you neglect air resistance, then you can solve for the horizontal distance using the formula:

dx=vixt

Where:
dx = horizontal distance
vix = initial horizontal velocity
t = time in flight

Now you can see that you have all the given you need.
vix= 2km/h
t = 0.25 hours

We use hours because you need the units to be the same. So just plug that in your equation and you will have your answer:

dx = vixt
=(2km/h)(0.25h)
=0.5km

This means that the answer to your question is B.

5 0

3 years ago

Infrared radiation _____. has wavelengths that are shorter than visible light is part of the visible light spectrum has waveleng

iren [92.7K]

Answer: has wavelengths that are longer than visible light

Explanation: Electromagnetic spectra comprises of different electromagnetic waves which are arranged in order of increasing wavelengths or decreasing energies.

In order from highest to lowest energy, the waves are arranged as: gamma rays, X-rays, ultraviolet radiation, visible light, infrared radiation, and radio waves.

$E=\frac{hc}{\lambda}$

E= energy

h= planck's constant

c= velocity of light

$\lambda$ = wavelength

As wavelength and energy are inversely related, the wave having higher wavelengths will be lowest in energy. Thus as infrared radiation have lower energy as compared to visible radiation. Thus infrared radiation have higher wavelength as compared to visible radiation.