1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Angelina_Jolie [31]
1 year ago
9

A simple pendulum has time period of 2s. It is called second pendulum. Fimd the length of second pendulum on earth and moon(gm=g

/6)
Physics
1 answer:
Margarita [4]1 year ago
4 0

The length of the second pendulum on earth is 1m and on the moon 1/6m.

Given:

The time period of a second pendulum T = 2s

By using the formula T = 2π √l/g we can calculate the length of the pendulum on earth and the moon.

Here g = acceleration due to gravity and

l = the length of the pendulum.

Now

l = g(T/ 2π)^2

l = 9.8 m/s^2(2s / 2 x 3.14)^2

le = 1 m

Now calculate the length of the pendulum on the moon

T =  2π √lm/gm      ∴ gm = ge/6

Now putting the value of g we get.

or 2 = 2 π √lm / ge/6

2 = 2 π √6lm / π ^2le

lm = le/6

now given le = 1m

lm = 1/6 m

Thus the length of the second pendulum on earth is 1m and on the moon 1/6m.

If you need to learn more about pendulum click here:

brainly.com/question/13764813

#SPJ4

You might be interested in
(a) What is the ionization energy of a hydrogen atom that is in the n = 6 excited state? (b) For a hydrogen atom, determine the
crimeas [40]

Answer:

(a) 0.3778 eV

(b) Ratio = 0.0278

Explanation:

The Bohr's formula for the calculation of the energy of the electron in nth orbit is:

E=\frac {-13.6}{n^2}\ eV

(a) The energy of the electron in n= 6 excited state is:

E=\frac {-13.6}{6^2}\ eV

E=-0.3778\ eV

Ionisation energy is the amount of this energy required to remove the electron. Thus, |E| = 0.3778 eV

(b) For first orbit energy is:

E=\frac {-13.6}{1^2}\ eV

E=-13.6\ eV

Ratio=\frac {E_6}{E_1}

Ratio=\frac {-0.3778}{-13.6}

Ratio = 0.0278

7 0
3 years ago
A car is moving at a rate of 72 km/hr .How far does car move when it stop after 4 seconds? ​
Zanzabum

Answer:

Assuming it starts at 72 kmph and hits a dead stop: Divide 72 by 60 for distance per minute. So, 1.2km per minute. 1.2km is 1200m and 4 seconds is one fifteenth of a minute.

Explanation:

5 0
3 years ago
In prokaryotic and eukaryotic cells the amount of water in the cell is kept at a steady state. The organelles
Len [333]

Answer:

A

Explanation:

It would not be C because prokaryotic cells don't have a nucleus. And if you're looking for a body in the cell that controls the nutrients and water it would be A.

3 0
3 years ago
The speed of light in vacuum is defined to be c = 299,792,458 m/s = 1 μ0ε0 . The permeability constant of vacuum is defined to b
Radda [10]

Explanation:

It is given that,

The speed of light in vacuum is, c = 299,792,458 m/s

The permeability constant of vacuum is, \mu_o=4\pi\times 10^{-7}\ N.s^2/C^2

Let \epsilon_o is the permittivity of free space. The relation between \mu_o,\epsilon_o\ and\ c is given by :

c=\dfrac{1}{\sqrt{\mu_o\epsilon_o}}

\epsilon_o=\dfrac{1}{c^2u_o}

\epsilon_o=\dfrac{1}{(299792458\ m/s)^2\times 4\pi\times 10^{-7}\ N.s^2/C^2}

\epsilon_o=8.85\times 10^{-12}\ C^2/N.m^2

Hence, this is the required solution.

3 0
3 years ago
Read 2 more answers
Calculate the ratio of the drag force on a jet flying at 1190 km/h at an altitude of 7.5 km to the drag force on a prop-driven t
Bond [772]

Answer:

\frac{D_{jet}}{D_{prop}}=2.865

Explanation:

Given data

Speed of jet Vjet=1190 km/h

Speed of prop driven Vprop=595 km/h

Height of jet 7.5 km

Height of prop driven transport 3.8 km

Density of Air at height 10 km p7.8=0.53 kg/m³

Density of air at height 3.8 km p3.8=0.74 kg/m³

The drag force is given by:

D=\frac{1}{2}CpAv^2\\

The ratio between the drag force on the jet to the drag force  on prop-driven transport is then given by:

\frac{D_{jet}}{D_{prop}}=\frac{(1/2)Cp_{7.5}Av_{jet}^2}{1/2)Cp_{3.8}Av_{prop}^2} \\\frac{D_{jet}}{D_{prop}}=\frac{p_{7.5}v_{jet}^2}{p_{3.8}v_{prop}}\\\frac{D_{jet}}{D_{prop}}=\frac{(0.53)(1190)^2}{(0.74)(595)^2}\\   \frac{D_{jet}}{D_{prop}}=2.865

4 0
3 years ago
Other questions:
  • Determine the specific heat of iron if 6.1 j of energy are needed to warm 1.50 g of iron from 20.0◦c to 29.0◦c?
    7·1 answer
  • Someone please help!
    15·1 answer
  • Can u plz help I'm failing and I have 2 weeks to get my grades up someone help me plz plz plz plz this is not a test ok it was h
    8·2 answers
  • The table lists several radioisotopes that have technological uses. Which radioisotope would be used by both archaeologists and
    10·2 answers
  • Use the diagram below to answer the following question:
    12·1 answer
  • Damian is texting while driving and ends up slamming into the back end of the car in front of him, which then strikes the car in
    11·1 answer
  • Plzzz helpp mee guysss!!! plzzzz
    15·2 answers
  • A 5.20-N force is applied to a 1.05-kg object to accelerate it rightwards across a friction-free surface. determine the accelera
    7·2 answers
  • Which statement best explains why light can travel with or without a medium?
    6·1 answer
  • This pendulum is at<br><br> minimum displacement<br> maximum displacement<br> equilibrium
    9·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!