Answer:
f = 409 Hz
Explanation:
We have,
Length of the open organ pipe, l = 0.29 m
Frequency of vibration of second overtone,
It is required to find the fundamental frequency of the pipe. For the open organ pipe, the frequency of second overtone is given by :
v is speed of sound
Let f is the fundamental frequency. It is given by :
The relation between f and f₂ can be written as :
So, the fundamental frequency of the pipe is 409 Hz.
The time when the particle is at rest is at 1.63 s or 3.36 s.
The velocity is positive at when the time of motion is at .
The total distance traveled in the first 10 seconds is 847 m.
<h3>When is a particle at rest?</h3>The time when the particle is at rest is calculated as follows;
s(t) = 2t³ - 15t² + 33t + 17
The velocity is positive at when the time of motion is as follows;
.
The total distance traveled in the first 10 seconds is calculated as follows;
Learn more about motion of particles here: brainly.com/question/11066673
