HClO₄ + KOH → KClO₄ + H₂O
HClO₄ - perchloric acid
KOH - potassium hydroxide
Answer: A. The compound CuCl is 500 times less soluble in sea water than it is in pure water.
pure water.
Explanation:
Any change in the equilibrium is studied on the basis of Le-Chatelier's principle.
This principle states that if there is any change in a equilibrium reaction, the equilibrium will shift in a direction so as to minimize the effect.
Thus when a common ion is introduced to an equilibrium reaction, the equilibrium will shift in a direction where the concentration of common ion is decreasing.


When common ion such as
from NaCl in sea water is introduced to an equilibrium reaction, the equilibrium will shift in a direction where the concentration of common ion is decreasing i.e. in the left side and thus solubility of CuCl further decreases.
Answer:
The correct option is the option;

Explanation:
The wavelength of a wave is the distance between two successive crests of the wave
Therefore, the wavelength, λ, is given by the fraction of the velocity, <em>v</em>, of the wave divided by the frequency, <em>f</em>, (the number of cycles that pass through a point) of the wave
Mathematically, we have;


Add me in snap chat and you will be the topper in your collage
Salushi_7