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Vsevolod [243]
3 years ago
10

When an atom gains an electron it becomes a ___ ion

Chemistry
2 answers:
Gnesinka [82]3 years ago
8 0
It becomes a negative ion. Also known as an anion.
uysha [10]3 years ago
4 0
When an atom gains an electron, it becomes a negative ion.
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With the aid of a balanced chemical equation explain Chemical Reactions and the Types Of Chemical Reaction
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Answer:

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1.)reactants: nitrogen and hydrogen; product: ammonia.

2.)reactants: magnesium hydroxide and nitric acid; products: magnesium nitrate and water.

3.)N 2 + 3H 2 → 2NH 3

4.)Mg(OH) 2 + 2HNO 3 → Mg(NO 3) 2 + 2H 2O.

5.)2NaClO 3 → 2NaCl + 3O 2

6.)4Al + 3O 2 → 2Al 2O 3

7.)N 2(g) + 3H 2(g) → 2NH 3(g)

Explanation:

''.''

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What is the name of the molecule below
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Answer:

2-octene

Explanation:

the 8-carbon chain (oct); has a double bond (ene) is on the 2nd carbon (2-)

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3 years ago
How do a single, double, and triple covalent bonds form?
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6 0
3 years ago
For the following reaction, 76.0 grams of barium chloride are allowed to react with 67.0 grams of potassium sulfate. barium chlo
Nataliya [291]

For the following reaction, 76.0 grams of barium chloride are allowed to react with 67.0 grams of potassium sulfate.

The reaction consumes _____ moles of barium chloride. The reaction produces _____ moles of barium sulfate and _____ moles of potassium chloride.

Answer: a) The reaction consumes 0.365 moles of barium chloride.

b) The reaction produces 0.365 moles of barium sulfate and 0.730 moles of potassium chloride.

Explanation:

To calculate the moles :

\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}    

\text{Moles of barium chloride}=\frac{76.0}{208g/mol}=0.365moles

\text{Moles of potassium sulphate}=\frac{67.0}{174g/mol}=0.385moles

BaCl_2(aq)+K_2SO_4(aq)\rightarrow BaSO_4(s)+2KCl(aq)

According to stoichiometry :

1 mole of BaCl_2 require 1 mole of K_2SO_4

Thus 0.365 moles of BaCl_2 will require=\frac{1}{1}\times 0.365=0.365moles  of K_2SO_4

Thus BaCl_2 is the limiting reagent as it limits the formation of product and K_2SO_4 is the excess reagent.

As 1 moles of BaCl_2 give = 1 moles of BaSO_4

Thus 0.365 moles of BaCl_2 give =\frac{1}{1}\times 0.365=0.365moles  of BaSO_4

As 1 moles of BaCl_2 give = 2 moles of KCl

Thus 0.365 moles of BaCl_2 give =\frac{2}{1}\times 0.365=0.730moles  of KCl

Thus the reaction consumes 0.365 moles of barium chloride. The reaction produces 0.365 moles of barium sulfate and 0.730 moles of potassium chloride.

6 0
3 years ago
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