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marin [14]
3 years ago
11

A chemist must dilute 58.0 ML of 69.6 M aqueous silver nitrate (AgNO3) solution until the concentration falls to 5.00 M. He'll d

o this by adding distilled water to the solution until it reaches a certain final volume.Calculate this final volume, in liters. Round your answer to 3 significant digits.
Physics
1 answer:
sdas [7]3 years ago
3 0
1929292929292929393939339
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A block of 7.80 kg kept on an inclined plane just begins to slide at an angle of inclination of 35.0°. Once it has been set into
Bas_tet [7]

Answer:

The answer is....i am sorry idk

8 0
4 years ago
Calculate the pressure exerted on the ground by a boy of a mass 60 kg if he stands on one foot.the area of the sole of his shoe
ddd [48]

Answer:

40 Kpa

Explanation:

150 cm2 = 0.015 m2

p \:  =  \frac{mg}{ a}  = 40000

8 0
3 years ago
You leave your home at 1pm. At 3pm, you are 100 km east of your house. What was your average velocity in km/hr
Rasek [7]

Answer:

50km/h

Explanation:

Average velocity = change in distance (or distance travelled) divided by/ the change in time (or time taken.)

The change in distance has been given as 100km.

The change in time is 3pm-1pm = 2 hours.

Therefore the average velocity was 100/2 = 50km/h (to the east).

Hope this helped!

4 0
3 years ago
Your in an escape room. Only its real and your oxygen runs out in 3 minutes unless you solve this problem, The problem :a ball i
alex41 [277]

The sum of the series allows to find the result for the total distance that the ball bounces is:

            total distance = 59.52 in

A series is a set of things or numbers related by a specific operation.

They indicate that the ball falls from an initial height y₀ = 30 in. and it bounces 50% of the height and the process is repeated until it stops, see attached.

Let's build a table to observe the sequence.

drop   height    rebound

   1        30          15

   2       15            7.5

   3        7.5         3.75

If we call the first term y₀  

The first bounce can be found.

                             y₁ = \frac{y_o}{2}

The second bounces.

                             y_2 = \frac{y_1}{2}  \\y_2 = \frac{y_o}{4}

The third bounce.

                             y_3  = \frac{y_2}{2}  \\y_3 = \frac{y_0}{ 8}

By observing this table we can construct a series of the form

 

      Total distance = y_o \ ( 1 + \frac{1}{2} + \frac{1}{4}+  \frac{1}{8} + ... +\frac{1}{2n} )

The sum of the serie has a result of

        sum  = 127/64 = 1,984

Let's calculate

     distance total  = 30 1,984

     Distance total = 59.52 cm

In conclusion, using the sum of the series we can find the result for the total distance that the ball bounces is:

            total distance = 59.52 in

Learn more here: brainly.com/question/8879163

4 0
3 years ago
Read 2 more answers
A plane is flying east at 135 m/s. The wind accelerates it at 2.18 m/s^2 directly northeast. After 18 s, what is the magnitude o
Korolek [52]

When we say directly northeast that is equivalent to 45˚ north of east.

First let us determine the north and east components of the acceleration using cos and sin functions:<span>

North = 2.18 * sin 45 
East = 2.18 * cos 45 

<span>Then we set to determine the east component of the plane’s displacement by calculating using the formula:

d = vi * t + ½ * a * t^2 
d = 135 * 18 + ½ * 2.18 * cos 45 * 18^2 
<span>d = 2430 + 353.16 * cos 45 = 2679.72 m</span>

Calculating for the north component:
North = ½ * 2.18 * sin 45 * 18^2 </span></span>

North = 249.72 m 

 

Hence magnitude is:

Magnitude = sqrt (2679.72^2 + 249.72^2)

Magnitude = 2,691. 33 m<span>

</span>

Calculating for angle:

Tan θ = North ÷ East <span>
<span>Tan θ = 249.72 m  ÷ 2679.72 m</span></span>

θ = 5.32°<span>


</span>

So the plane was flying at 2,691. 33 m at 5.32<span>°</span>

4 0
3 years ago
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