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3 years ago

Consider the Zn(s) + Cu^+2(aq) --->Zn^+2(aq) + Cu(s) system. Which element was the electron donor?

1 answer:

3 0

Basically, electron donors are the elements that give up there electrons, so they will be oxidized. In the reaction, Zn(s) oxidizes into Zn^+2, so the 2 electrons are bing donated to the Cu^2+. Thus Zn(s) is the electron donor

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Arrange the elements in order of increasing ionization energy: K,Br

Ilya [14]

K has the lowest and Br has the higher

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3 years ago

Metals have high melting and boiling points and are often shiny and silvery. Which of the blocks are metals?

DanielleElmas [232]

Answer:

S and p blocks elements are considered metals while d-block elements are considered transition metals.

Explanation:

s-block consist of lithium, sodium, potassium, rubidium, cesium and francium metals.

All are these called alkali metals.

These metals have one valance electron.

These metals are soft and having low density.

They easily lose their one valance electron and form cation with +1 charge.

They have low melting points.

P- block elements includes beryllium, magnesium, calcium, strontium, barium, radium metals.

They are called alkaline earth metals.

All are these have two valance electrons.

They easily lose their valance electrons and form cation with charge of +2.

These metals are also very soft.

They form salt with halogens.

They are also very reactive metals.

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3 years ago

Porfavor alguien que me explique los Cambios bioquimicos en los musculos ,sangre e higado durante los ejercicios fisicos y como

german

Answer:

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3 years ago

What is the concentration of OH − and pOH in a 0.00066 M solution of Ba ( OH ) 2 at 25 ∘ C? Assume complete dissociation.

Allushta [10]

<u>Answer:</u> The hydroxide ion concentration and pOH of the solution is $1.32\times 10^{-3}M$ and 2.88 respectively

<u>Explanation:</u>

We are given:

Concentration of barium hydroxide = 0.00066 M

The chemical equation for the dissociation of barium hydroxide follows:

$Ba(OH)_2\rightarrow Ba^{2+}+2OH^-$

1 mole of barium hydroxide produces 1 mole of barium ions and 2 moles of hydroxide ions

pOH is defined as the negative logarithm of hydroxide ion concentration present in the solution

To calculate pOH of the solution, we use the equation:

$pOH=-\log[OH^-]$

We are given:

$[OH^-]=(2\times 0.00066)=1.32\times 10^{-3}M$

Putting values in above equation, we get:

$pOH=-\log(1.32\times 10^{-3})\\\\pOH=2.88$

Hence, the hydroxide ion concentration and pOH of the solution is $1.32\times 10^{-3}M$ and 2.88 respectively

3 0

3 years ago

The turnover number is defined as the maximum number of substrate molecules that can be converted into product molecules per uni

Nataliya [291]

Answer:

Explanation:

turn over number = R max / [E]t = K2

From given , R max = 249 * 10 ^ -6 mol. L^-1

T [E]t = 2.23 n mol. L^-1

= 2.23 * 10^-9 mol. L^-1

Putting values in above equation,

= 111.65 * 10^3 S^-1

Turn over number is maximum no of substrate molecule that can be converted into product molecules for unit time by enzyme molecule.

5 0

3 years ago