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soldier1979 [14.2K]
4 years ago
14

When you whirl a tin can in a horizontal circle overhead, the force that holds the can in the circular path acts in a direction

Physics
2 answers:
elena-14-01-66 [18.8K]4 years ago
8 0

When an object is in circular path then the net force on the object is always towards the center of the path

Now here the position of the tin is overhead above us

So the center of the circular path will lie just below it

So the net force is also in the direction of the center

So here we will have

Net force downwards towards the center

And this is along the direction of gravity

Now the correct answer is

<u>parallel to gravity</u>

Igoryamba4 years ago
5 0
<h2>Answer:</h2>

<u>The correct choice is</u><u> (A) Inward</u>

<h2>Explanation:</h2>

A force that acts on a body moving in a circular path and is directed towards the center around which the body is moving is called centripetal force. In the given case when we whirl a tin can in a horizontal circle overhead, the force that holds the can in the circular path acts in a direction inwards because it is the force that holds the tin to keep inside the circular path.

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wo ships, one 200200 metres in length and the other 100100 metres in length, travel at constant but different speeds. When trave
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Answer:

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Explanation:

The length of the ships are;

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Ship 2 = 100 m

The time it takes for the ships to completely cross each other when travelling in opposite directions = 10 seconds

The time it takes both ships to cross each other when travelling in the same direction = 25 seconds

Let x represent the speed of the first ship, ship 1, and y represent the speed of the second ship, ship, 2, we have;

(x + y) × 10 = 200 + 100 = 300

10·x + 10·y = 300...(1)

(x - y) × 20 = 200 + 100 = 300

20·x - 20·y = 300...(2)

Multiply equation (1) by 2, to get;

(x + y) × 10 × 2 = 300 × 2

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Adding equation (1) to equation (3) gives;

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40·x = 900

x = 900/40 = 22.5

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From equation (1), we have;

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y = (300 - 10·x)/10 = (300 - 10×22.5)/10 = 7.5

y = 7.5

The speed of the second ship, ship 2 = y = 7.5 m/s

Therefore, the faster ship is ship 1 with a speed of 22.5 m/s

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