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3 years ago

What happens to the strength of an electromagnet if the number of loops of wire is increased?

Physics

1 answer:

luda_lava [24]3 years ago

8 0

Answer:

If you coil the wire around and around, it will make the magnetic force stronger, but it will still be pretty weak. ... The strength of an electromagnet can be increased by increasing the number of loops of wire around the iron core and by increasing the current or voltage.

Explanation:

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To play ice hockey, each player needs ________. skates rollerblades crosses sunglasses

ipn [44]

Answer:

skates

Explanation:

Ice hockey is considered to be an extremely tough sport in which there are twelve players who fights over small 3" puck which can be launched like a missile. If one plays ice hockey he should must have necessary equipment to support his sport. These equipment include Ice Skates,Helmet with Cage and Mouth-guard:, Hockey stick, Hockey pants,Hockey gloves, shoulder pads, elbow pads, Shin Guard:Neck guard and Jockstrap (men) or Pelvic protector (women).

<em>Here we can see that correct choice is ice skate which is important for supporting player's ankles while playing ice hockey.</em>

Hope it helps!

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3 years ago

Calculate

Fed [463]

The speed of the spacecraft in this orbit

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3 years ago

Only about 50% of the solar energy directed toward Earth penetrates directly to the surface. Explain what happens to the rest of

Tresset [83]

Answer:

it is absorbed or reflected by the atmosphere

Explanation:

In the case when approx 50% only of the solar energy would be directed towards earth and it would be penetrates directly to the surface so the rest or remaining of the radiation would be either absorbed or refected by the atmosphere

So as per the given situation the above represent the answer

hence, the same is to be considered and relevant

4 0

3 years ago

Read 2 more answers

What are the characteristics of low energy waves

Ray Of Light [21]

Higher frequency,higher energy,shorter wavelength

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3 years ago

Two forces, F₁ and F₂, act at a point. F₁ has a magnitude of 8.00 N and is directed at an angle of 61.0° above the negative x ax

kirill115 [55]

1) -7.14 N

2) +2.70 N

3) 7.63 N

Explanation:

In order to find the x-component of the resultant force, we have to resolve each force along the x-axis.

The first force is 8.00 N and is directed at an angle of 61.0° above the negative x axis in the second quadrant: this means that the angle with respect to the positive x axis is

$180^{\circ}-61^{\circ}$

so its x-component is

$F_{1x}=(8.00)(cos (180^{\circ}-61^{\circ}))=-3.88 N$

F₂ has a magnitude of 5.40 N and is directed at an angle of 52.8° below the negative x axis in the third quadrant: so, its angle with respect to the positive x-axis is

$180^{\circ}+52.8^{\circ}$

Therefore its x-component is

$F_{2x}=(5.40)(cos (180^{\circ}+52.8^{\circ}))=-3.26 N$

So, the x-component of the resultant force is

$F_x=F_{1x}+F_{2x}=-3.88+(-3.26)=-7.14 N$

In order to find the y-component of the resultant force, we have to resolve each force along the y-axis.

The first force is 8.00 N and is directed at an angle of 61.0° above the negative x axis in the second quadrant: as we said previously, the angle with respect to the positive x axis is

$180^{\circ}-61^{\circ}$

so its y-component is

$F_{1y}=(8.00)(sin (180^{\circ}-61^{\circ}))=7.00 N$

F₂ has a magnitude of 5.40 N and is directed at an angle of 52.8° below the negative x axis in the third quadrant: as we said previously, its angle with respect to the positive x-axis is

$180^{\circ}+52.8^{\circ}$

Therefore its y-component is

$F_{2y}=(5.40)(sin (180^{\circ}+52.8^{\circ}))=-4.30 N$