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goldfiish [28.3K]
3 years ago
5

What type of reaction is shown below? CaCl2 (aq) + MgSO4 (aq) --> CaSO4 (s) + MgCl2 (aq)

Chemistry
1 answer:
nikitadnepr [17]3 years ago
5 0
Metathesis reaction
AB+CD=AD+BC
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Using the bond energy data from your text (or the internet), determine (show calculations for) the approximate enthalpy change ,
aleksley [76]

Answer:

∆H=  <u>438 KJ/mol</u>

Explanation:

First, we have to find the <u>energy bond values</u> for each compound:

-) Cl-Cl = 243 KJ/mol

-) F-F = 159 KJ/mol

-) F-Cl = 193 KJ/mol

If we check the reaction we can calculate the <u>number of bonds</u>:

Cl_2_(_g_)~+~3F_2_(_g_)~->~2ClF_3_(_g_)

In total we will have:

-) Cl-Cl = 1

-) F-F = 3

-) F-Cl = 6

With this in mind. we can calculate the <u>total energy for each bond</u>:

-) Cl-Cl = (1*243 KJ/mol) = 243 KJ/mol

-) F-F = (3*159 KJ/mol) = 477 KJ/mol

-) F-Cl = (6*193 KJ/mol) = 1158 KJ/mol

Now, we can calculate the total energy of the <u>products</u> and the <u>reagents</u>:

Reagents = 243 KJ/mol + 477 KJ/mol = 720 KJ/mol

Products = 1158 KJ/mol

Finally, to calculate the total enthalpy change we have to do a <u>subtraction</u> between products and reagents:

∆H= 1158 KJ/mol-720 KJ/mol = <u>438 KJ/mol</u>

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Once a slide is prepared and placed onto the microscope, the magnification and focus need to be altered. Describe how to change
Harlamova29_29 [7]

Answer:

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Explanation:

我實際上不知道答案,我只是為了點我實際上不知道答案,我只是為了點數而這樣做,哈哈,祝你好運哈哈數而這樣做,哈哈,祝你好運哈哈

5 0
3 years ago
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If the accepted value for the mass of an object is 20.0g and the student found that the mass of the object was 20.5g what is the
NikAS [45]

Answer:

Results

The percent error between 20 and 20.5 is 2.5%

Explanation:

Percent Error = | (20.5 − 20) / 20 | × 100 = | (0.5) / 20 | × 100 = | 0.025 | × 100 = 2.5% (three decimal places)Percent Error = 2.5%

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Which form of energy is stored chemical energy and example of?
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D

Explanation:

I THINK. HOPE THIS HELPS

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Which of the following statements is true? Protons have a mass that contributes significantly to the mass of the atomic nucleus.
Lunna [17]
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