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sergij07 [2.7K]
3 years ago
12

3 ways pollution gets into neighborhoods

Physics
1 answer:
SashulF [63]3 years ago
7 0

Answer:

1. Leaving trash on the ground and not picking it up.

2. Polluting the lake, if your neighborhood has one.

3. Outside people come and dump their waste to your neighborhood.

Hope this helps!

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If a woman weighs 125 lb, her mass expressed in kilograms is x kg, where x is
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The first thing you should know to solve this problem is the conversion of pounds to kilograms:
 1lb = 0.45 Kg
 We can solve this problem by a simple rule of three
 1lb ---> 0.45Kg
 125lb ---> x
 Clearing x we have:
 x = ((125) / (1)) * (0.45) = 56.25 Kg.
 Answer
 her mass expressed in kilograms is 56.25 Kg.
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Most new jobs in the United States will be in the _____.
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in the service producing sector

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The formation of bonds releases energy. 
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A distracted driver is driving towards a turn where the edge of the road leads into a 75.0 m cliff. The velocity of the vehicle
Vlada [557]

As long as the car is on the road, it moves with a constant speed of 80km/h.

As soon as the car starts to fall down the cliff, it follows a parabolic motion. It means that it still moves with constant speed along the x axis, but it also starts to move along the y axis, with constant acceleration (i.e. the acceleration due to gravity).

The good thing about parabolic motions is that the two motions along the x and y axes are completely separable.

So, first of all, we need to know how long it takes for an object to fall for 75m. The equation of a constantly accelerated motion is

s=s_0+v_0t+\dfrac{1}{2}at^2

Where s_0 is the initial position, v_0 is the initial speed, and a is the constant rate of acceleration. In our case, we start from an initial height of 75m, an initial (vertical!) speed of zero, and our acceleration is -g. So, our equation becomes

s=75-\dfrac{g}{2}t^2

And we want to solve for the time when s=0 (i.e. we want to know how long will it take for the object to reach the ground). We have

0=75-\dfrac{g}{2}t^2 \iff 75=\dfrac{g}{2}t^2 \iff \dfrac{2\cdot75}{g}=t^2 \iff t=\sqrt{\dfrac{150}{g}}

(I'm discarding the negative solution because it wouldn't make sense)

Now that we've used the vertical motion to find out the falling time, we can go back to the horizontal motion. We know that the car moves for a certain amount of time at a certain speed. So, we simply have to plug our values in the s=vt equation, to get

s=80\sqrt\dfrac{150}{g}}

This is how far from the base of the cliff the vehicle lands.

3 0
3 years ago
What is the difference between m/s and m.s.​
vfiekz [6]

Answer

m/s rate of change of dispalcement per sec. ie velocity

m/s^2 is (m/s)/s ie rate of change of velocity per sec. ie accelerationplanation:

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