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3 years ago

9

What units are used for volume?

2 answers:

anyanavicka [17]3 years ago

8 0

Cubic centimeters for the volume of a solid.
Liters for volume of a liquid.

Ne4ueva [31]3 years ago

6 0

Any unit of length, when cubed, is a perfectly good unit of volume.

Examples:
-- centimeter³
-- meter³
-- inch³
-- foot³
-- yard³

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A rocket travels 1.3 km in 62 ms. What is its average speed in m⋅s−1? Do not give your answer in scientific notation. The answer

hjlf

Answer:

Average speed = 0.35 m/s

Explanation:

Given the following data;

Distance = 1.3 Km

Time = 62 minutes

To find the average speed in m/s;

First of all, we would convert the quantities to their standard unit (S.I) of measurement;

Conversion:

1.3 kilometres to meters = 1.3 * 1000 = 1300 meters

For time;

1 minute = 60 seconds

62 minutes = X

Cross-multiplying, we have;

X = 62 * 60

X = 3720 seconds

Now, we can calculate the average speed in m/s using the formula;

$Speed = \frac {distance}{time}$

$Speed = \frac {1300}{3720}$

Average speed = 0.35 m/s

7 0

3 years ago

A 5kg mass is pushed with a force of 10N for a distance of 2.5 meters. The work done is

Aliun [14]

W = 25 J

Explanation:

Work done on an object is defined as

$W = Fd = (10\:\text{N})(2.5\:\text{m}) = 25\:\text{J}$

7 0

2 years ago

An 850 kg elevator is accelerating upwards at 3.0 m/s2. Calculate the tension in the cable.

sveta [45]

Answer:

10880N

Explanation:

We are given that

Mass of elevator, m=850 kg

Acceleration, $a=3m/s^2$

$g=9.8m/s^2$

We have to find the tension in the cable.

We know that

When elevator is accelerating upward then tension in the cable

$T=m(a+g)$

Using the formula

$T=850(3+9.8)$

$T=10880N$

7 0

2 years ago

In Millikan’s experiment, the oil droplets acquire one or more negative charges by combining with the negative charges that are

alina1380 [7]

Answer:

$-9.6\cdot 10^{-19} C$

Explanation:

The charge of a single electron is:

$q=-1.60\cdot 10^{-19} C$

If a droplet contains N electrons, then its charge would be:

$Q=Nq$

In this case, the droplet has

N = 6

electrons, so its total charge is

$Q=(6)(-1.60\cdot 10^{-19}C)=-9.6\cdot 10^{-19} C$

7 0

3 years ago

A 28 kg mass suspends from a light rope 18 m long & is held to one side by the horizontal force, F, as shown below.

frutty [35]

Answer: 215.15 N

Explanation:

If we draw a free body diagram of the mass we will have the following:

$\sum{F_{x}}=-Tcos\theta + F=0$ (1)

$\sum{F_{y}}=Tsin\theta - mg=0$ (2)

Where $T$ is the tension force of the rope, $m=28 kg$ the mass, $g=9.8 m/s^{2}$ the acceleration due gravity and $mg$ is the weight.

On the other hand, we can calculate $\theta$ as follows:

$cos\theta=\frac{s}{l}$

$\theta=cos^{-1}(\frac{s}{l})$

Where $s=11.1 m$ and $l=18 m$

$\theta=cos^{-1}(\frac{11.1 m}{18 m})$

$\theta=51.9\°$ (3)

Now, we firstly need to find $T$ from (2):

$T=\frac{mg}{sin\theta}$ (4)

$T=\frac{(28 kg)(9.8 m/s^{2})}{sin(51.9\°)}$

$T=348.69 N$ (5)

Substituting (5) in (1):

$F=Tcos\theta$ (6)

$F=348.69 N cos(51.9\°)$

Finally:

$F=215.15 N$

8 0

3 years ago