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Anna35 [415]
3 years ago
9

Calculate the value of the diffusion coefficient D (in m2/s) at 547°C for the diffusion of some species in a metal; assume that

the values of D0 and Qd are 5.6 × 10-5 m2/s and 177 kJ/mol, respectively.
Chemistry
1 answer:
svetlana [45]3 years ago
6 0

Answer : The value of diffusion coefficient is, 2.97\times 10^{-16}m^2/s

Explanation :

Formula used :

D=D_o\times \exp \left(-\frac{Q_d}{RT}\right )

where,

D = diffusion coefficient = ?

D_o = 5.6\times 10^{-5}m^2/s

Q_d = 177kJ/mol

R = gas constant = 8.314 J/mol.K

T = temperature = 547^oC=273+547=820K

Now put all the given values in the above formula, we get:

D=5.6\times 10^{-5}m^2/s\times \exp \left(-\frac{177kJ/mol}{(8.314J/mol.K)\times (820K)}\right )

D=2.97\times 10^{-16}m^2/s

Thus, the value of diffusion coefficient is, 2.97\times 10^{-16}m^2/s

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Hello there!

In this case, according to the given chemical reaction, it is first necessary to compute the moles of reacting LiOH given its molar mass:

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Best regards!

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